Question

所以我的问题是让用户输入数小时的更短的方法，而不是我制作一个巨大的单词列表，说明用户输入1是否使其成为“一个”等。我觉得我应该使用pop但同时，我觉得我怎样才能获得用户输入以从列表中获取某个单词。

-- table definition
create table Particle_counter_HiSam ( time_utc  timestamp, ... );

-- load data
load data infile 'data.csv' 
into table Particle_counter_HiSam
fields terminated BY ',' ESCAPED BY ""
lines terminated by '\r\n'
(@var1, c2, ....)
SET time_utc = STR_TO_DATE(@var1,'%m/%d/%Y %H:%i:%S');

Answer 1

将输入转换为整数，然后使用它们索引已有的数组。简化示例：

hours = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve"]

hour = int(input("Please enter the hour: "))

print(hours[hour-1]  + " O'clock")
# Subtract one from hour because arrays start at index 0 but hours starts at "one"

获取用户输入数字并将其转换为单词？

1 个答案: