Debug Assertion Failed!
Program: ...nts\Visual Studio 2015\Projects\Project 5\Debug\Project 5.exe
File: minkernel\crts\ucrt\src\appcrt\heap\debug_heap.cpp
Line: 892
Expression: is_block_type_valid(header->_block_use)
For information on how your program can cause an assertion
failure, see the Visual C++ documentation on asserts.
(Press Retry to debug the application)
程序正确运行并输出所有内容，并抛出此错误。我还没有找到任何关于这意味着什么或如何寻找或修复它的好解释。这是（难以置信的丑陋和写得不好）代码的完整副本：
#include <iostream>
using namespace std;
/* a class for storing a Binary Tree */
template <class Type>
class BinaryTree {
protected:
Type parentArray[10];
Type childArray[10];
public:
BinaryTree();
BinaryTree(int& k);
~BinaryTree();
BinaryTree(BinaryTree<Type>& bt);
void operator= (BinaryTree<Type>& bt);
friend ostream& operator<< (ostream& s, BinaryTree<Type> bt) {
s << "[ ";
bt.inorder(bt.getRoot());
s << "]" << endl;
return s;
};
int size();
int height();
int getLeft(int k);
int getRight(int k);
void preorder(int k);
void inorder(int k) {
// do I have a left child?
if ((getLeft(k)) != -1) {
// if yes inorder (left child)
inorder(getLeft(k));
};
// output k
cout << k << " ";
// do I have a right child?
if ((getRight(k)) != -1) {
// if yes inorder (right child)
inorder(getRight(k));
};
};
void postorder(int k);
void setRoot(Type& val);
void setParent(Type* child, Type* parent);
void setLeft(Type& val);
void setRight(Type& val);
int getRoot();
};
/* default constructor */
template <class Type>
BinaryTree<Type>::BinaryTree() {
parentArray = new ArrayClass<Type>();
childArray = new ArrayClass<Type>();
};
/* non-empty constructor */
template <class Type>
BinaryTree<Type>::BinaryTree(int& k) {
// parentArray = new Type[k];
// childArray = new Type[k];
};
template <class Type>
BinaryTree<Type>::~BinaryTree() {
delete[] parentArray;
delete[] childArray;
};
template <class Type>
BinaryTree<Type>::BinaryTree(BinaryTree<Type>& bt) {
for (int i = 0; i < bt.size(); i++) {
parentArray[i] = bt.parentArray[i];
childArray[i] = bt.childArray[i];
};
};
template <class Type>
void BinaryTree<Type>::operator= (BinaryTree<Type>& bt) {
};
/* return the size of the tree using the length of the parent array */
template <class Type>
int BinaryTree<Type>::size() {
return (sizeof(parentArray)/sizeof(*parentArray));
};
template <class Type>
int BinaryTree<Type>::height() {
return 5;
};
template <class Type>
int BinaryTree<Type>::getLeft(int k) {
// if the parent array value of the given number is k and
// the child array value indicates it is a left child
for (int i = 0; i < size(); i++) {
if ((parentArray[i] == k) && (childArray[i] == 0)) {
// return that value
return i;
};
};
return -1;
};
template <class Type>
int BinaryTree<Type>::getRight(int k) {
// if the parent array value of the given number is k and
// the child array value indicates it is a right child
for (int i = 0; i < size(); i++) {
if ((parentArray[i] == k) && (childArray[i] == 1)) {
// return that value
return i;
};
};
return -1;
};
template <class Type>
void BinaryTree<Type>::preorder(int k) {
// output k
cout << k << " ";
// do I have a left child?
if ((getLeft(k)) != -1) {
// if yes preorder left child
preorder(getLeft(k));
};
// do I have a right child?
if ((getRight(k)) != -1) {
// if yes preorder right child
preorder(getRight(k));
};
};
template <class Type>
void BinaryTree<Type>::postorder(int k) {
// do I have a left child?
if ((getLeft(k)) != -1) {
// if yes inorder (left child)
inorder(getLeft(k));
};
// do I have a right child?
if ((getRight(k)) != -1) {
// if yes inorder (right child)
inorder(getRight(k));
};
// output k
cout << k << " ";
};
template <class Type>
void BinaryTree<Type>::setRoot(Type& val) {
// if the given value is the root of the tree then set
// its index in the parent and child arrays to -1
parentArray[val] = -1;
childArray[val] = -1;
};
template <class Type>
void BinaryTree<Type>::setParent(Type* child, Type* parent) {
// set a given value as the parent of a given value
parentArray[(*child)] = *parent;
};
template <class Type>
void BinaryTree<Type>::setLeft(Type& val) {
// set a given value in the child array to indicate a left child
childArray[val] = 0;
};
template <class Type>
void BinaryTree<Type>::setRight(Type& val) {
// set a given value in the child array to indicate a right child
childArray[val] = 1;
};
template <class Type>
int BinaryTree<Type>::getRoot() {
// find the root value of the tree
for (int i = 0; i < size(); i++) {
if (parentArray[i] == -1) {
// and return it
return i;
};
};
};
int main() {
int* val1 = new int;
int* val2 = new int;
int* val3 = new int;
int count;
cin >> count;
BinaryTree<int> bt(count);
for (int i = 0; i < count; i++) {
cin >> *val1;
cin >> *val2;
cin >> *val3;
if (i == 0) {
bt.setRoot(*val1);
};
if (*val2 != -1) {
bt.setParent(val2, val1);
bt.setLeft(*val2);
}
if (*val3 != -1) {
bt.setParent(val3, val1);
bt.setRight(*val3);
}
val1 = new int;
val2 = new int;
val3 = new int;
};
cout << bt.size() << endl;
bt.postorder(bt.getRoot());
cout << endl;
bt.preorder(bt.getRoot());
cout << endl;
delete val1;
delete val2;
delete val3;
};
BinaryTree类中的一些函数还没有完成，只是在其中有填充垃圾用于测试。
答案 0 :(得分：1)
您的BinaryTree析构函数始终确保：
delete[] parentArray;
delete[] childArray;
不幸的是，该类的一个构造函数不会new这些数组中的任何一个。因此，析构函数最终尝试delete一对未初始化的垃圾指针。
这个班级violates the Rule Of The Three也可能，但我没有对此进行充分分析。
编辑：正如评论中指出的那样，这些不是指针;所以这是错的，但出于其他原因。