Question

以下是我正在处理的代码。

def gold_room
  puts "This room is full of gold. How much do you take?"

  print "> "
  choice = $stdin.gets.chomp

  # this line has a bug, so fix it
  if choice.include?("0") || choice.include?("1")
    how_much = choice.to_i
  else
    dead("Man, learn to type a number.")
  end

  if how_much < 50
    puts "Nice, you're not greedy, you win!"
    exit(0)
  else
    dead("You greedy bastard!")
  end
end

def bear_room
  puts "There is a bear here."
  puts "The bear has a bunch of honey."
  puts "The fat bear is in front of another door."
  puts "How are you going to move the bear?"
  bear_moved = false

  while true
    print "> "
    choice = $stdin.gets.chomp
    if choice == "take honey"
      dead("The bear looks at you then slaps your face off.")
    elsif choice == "taunt bear" && !bear_moved
      puts "The bear has moved from the door. You can go through it now."
      bear_moved == true
    elsif choice == "taunt bear" && bear_moved
      dead("The bear gets pissed off and chews your leg off.")
    elsif (choice == "open door") && bear_moved
      gold_room
    else
      puts "I got no idea what that means."
    end
  end
end

def cthulhu_room
  puts "Here you see the great evil Cthulhu."
  puts "He, it, whatever stares at you and you go insane."
  puts "Do you flee for your life or eat your head?"

  print "> "
  choice = $stdin.gets.chomp

  if choice.include? "flee"
    start
  elsif choice.include? "head"
    dead("Well that was tasty!")
  else
    cthulhu_room
  end
end

def dead(why)
  puts why, "Good job!"
  exit(0)
end

def start
  puts "You are in a dark room."
  puts "There is a door to your right and left."
  puts "Which one do you take?"

  print "> "
  choice = $stdin.gets.chomp

  if choice == "left"
    bear_room
  elsif choice == "right"
    cthulhu_room
  else
    dead("You stumble around the room until you starve.")
  end
end

start

当我尝试在OS X的终端上运行它时，我得到了这个：

You are in a dark room.
There is a door to your right and left.
Which one do you take?
> left
There is a bear here.
The bear has a bunch of honey.
The fat bear is in front of another door.
How are you going to move the bear?
> taunt bear
The bear has moved from the door. You can go through it now.
> open door
I got no idea what that means.  # should go to gold_room, new area
>

我希望程序在输入＆＃34;打开门＆＃34;后把我带到黄金房间，而是转到barf消息并重新启动while循环。

我认为我已经弄乱了范围，但我做了研究，仍然不明白为什么变量没有被操纵，或者为什么我没有得到我期望的结果。< / p>

Answer 1

您的问题可能是您写的是bear_moved == true而不是bear_moved = true。

Answer 2

它bear_moved = true而非bear_moved == true

elsif choice == "taunt bear" && !bear_moved
      puts "The bear has moved from the door. You can go through it now."
      bear_moved = true
elsif choice == "taunt bear" && bear_moved

Answer 3

bear_moved变量应该接收布尔值，而不是在方法的第14行将其与true进行比较。

Answer 4

我认为你要确保当熊被嘲弄并且它不动时它应该移动熊，如果熊移动则不再检查。解决方案应该是删除elsif choice == "taunt bear" && !bear_moved上的比较运算符，将bear_moved更改为=而不是==

 while true
    print "> "
    choice = $stdin.gets.chomp
    if choice == "take honey"
      dead("The bear looks at you then slaps your face off.")
    elsif choice == "taunt bear" && !bear_moved
      puts "The bear has moved from the door. You can go through it now."
      bear_moved = true
    elsif choice == "taunt bear" && bear_moved
      dead("The bear gets pissed off and chews your leg off.")
    elsif (choice == "open door") && bear_moved
      gold_room
    else
      puts "I got no idea what that means."
    end
  end

文本冒险中的ruby变量范围错误

4 个答案: