Question

我开始使用Visual C ++，我正在尝试编写一个使用Arduino发送和接收某些数据的程序。但是，它似乎没有正常工作。例如，当使用Compare :: String时，即使我从Arduino发送完全相同的单词，它也会返回1而不是0。

可视化C ++代码如下：

private: System::Void backgroundWorker1_DoWork(System::Object^  sender, System::ComponentModel::DoWorkEventArgs^  e) {
    while (true)
    {
        try {
            String^ tempVal = Arduino->ReadLine();
            this->SetText(tempVal); //Calls the secure method for analyse the incoming data
            Arduino->DiscardInBuffer();
        }
        catch (TimeoutException^) {
        }
    }
}
delegate void SetTextDelegate(String^ text);
private: String^ IDemitter;
private: String^ Subred;
private: String^ Data;
private: String^ Options;
private: int Memoria;
private: void SetText(String^ texto)
{

    if (this->textReceive->InvokeRequired)
    {
        SetTextDelegate^ d = gcnew SetTextDelegate(this, &MyForm::SetText);
        this->Invoke(d, gcnew array<Object^> { texto });
    }
    else
    {

        if (String::Compare(texto, "DATA") == 1) { //Theoretically it should be 0, but it returns 1
            this->Arduino->WriteLine("OK");
            this->textReceive->Text = "OK";
            Memoria = 1; 
            texto = "0";
        }
        else if ((Memoria == 1) && (String::Compare(texto, "0") != 0)) { //It never reaches this stage... 
            IDemitter = texto;
            this->Arduino->WriteLine("OKID");
            this->textReceive->Text = "OKID";
            Memoria = 2;
            texto = "0";
        }
        else if ((Memoria == 2) && (String::Compare(texto, "0") != 0)) {
            Subred = texto;
            this->Arduino->WriteLine("OKSUB");
            Memoria = 3;
            texto = "0";
        }
        else if ((Memoria == 3) && (String::Compare(texto, "0") != 0)) {
            Options = texto;
            this->textReceive->Text = "OKOPT";
            this->Arduino->WriteLine("OKOPT");
            Memoria = 4;
            texto = "0";
            if (Options != "9") {
                this->ProcessData(IDemitter, Subred, Options);
            }
        }
        else if ((Memoria == 4) && (String::Compare(texto, "0") != 0) && (Options=="9")) {
            Data = texto;
            this->Arduino->WriteLine("OKDATA");
            this->textReceive->Text = "OKDATA";
            Memoria = 5;
            texto = "0";
            this->ProcessData(IDemitter, Subred, Options, Data);
        }
    }
}

简化的Arduino代码如下。

String confirmation;

void setup () {
Serial.begin(9600);
while(!Serial) { ; }
}

void loop () {

while(confirmation!="OK"){
Serial.println("DATA");
delay(5000);
confirmation=Serial.readString();
}
Serial.print("3"); //IDemitter
while(confirmation!="OKID"){
confirmation=Serial.readString();
}
Serial.print("2"); //Subred
while(confirmation!="OKSUB"){
confirmation=Serial.readString();
}
Serial.print("7"); // Options
while(confirmation!="OKOPT"){
confirmation=Serial.readString();
}

我的想法是在收到所有参数后在ProcessData（）中运行，但我认为它应该更加困难。任何帮助将非常感激。

Answer 1

在Arduino程序发送的“DATA”字符串中附加换行符。然后，PC的readline应该可以正常工作。

Visual C ++：使用Arduino通过串口进行不成功的通信

1 个答案: