Question

我有一个JavaScript数组，其中包含一些在请求创建用户帐户时无法使用的单词。

我正在尝试遍历请求的帐户并针对字词过滤器进行检查。如果它们包含任何单词，则该值将移动到“无效帐户”数组。

// Create our arrays
var blacklist = ["admin", "webform", "spoof"];
var newAccounts = ["admin1@google.com", "interweb@google.com", "puppy@google.com"];
var invalidAccounts = [];

// I need to check if any of the new accounts have matches to those in the blacklist. 
// admin1@google.com would need to be pushed into the invalidAccounts array because it 
// contains the word admin. Although interweb contains the word web, it does not contain 
// the full word, webform, so should be ignored.

// Loop over the blacklist array
for(var x = 0; x < blacklist.length; x++){
  if(blacklist[x].indexOf(newAccounts) > -1){
    alert(blacklist[x] + " is in the blacklist array");
    // Push the newAccounts value into the invalidAccounts array since it contains
    // a blacklist word.
  } else {
    alert('no matches');
  }
}

我需要在上面的代码中进行哪些更改才能使其与提到的部分字符串匹配？

上述代码的小提琴：https://jsfiddle.net/1qwze81o/

Answer 1

你可能不需要使用所有这些，但它应该是有帮助的：

var blacklist = ["admin", "webform", "spoof"];
var newAccounts = ["admin1@google.com", "interweb@google.com", "puppy@google.com"];
var invalidAccounts = [];

// transform each email address to an object of the form:
// { email: string, valid: boolean }
var accountObjects = newAccounts.map(function (a) {
    return { email: a, valid: true };
});

// loop over each account
accountObjects.forEach(function (account) {
    // loop over the blacklisted terms
    blacklist.forEach(function (blacklisted) {
        // check to see if your account email address contains a black listed term
        // and set the valid property accordingly
        account.valid = account.email.search(blacklisted) === -1;
    });
});

// filter accountObjects, validAccounts will now contain an array of valid objects
var validAccounts = accountObjects.filter(function (a) {
    return a.valid;
});

// back to the original type of a string array
var validEmailAddresses = validAccounts.map(function (a) {
    return a.email;
});

Answer 2

我修了一些东西......

for (var x = 0; x < newAccounts.length; x++) // loop through new accounts
{
    // for every account check if there is any match in blacklist array
    for (var y = 0; y < blacklist.length; y++) 
    {
      // if there is match do something 
      if (newAccounts[x].indexOf(blacklist[y]) > -1)
      {
          alert(newAccounts[x] + " is in the blacklist array");
          break;
      }
  }

}

Answer 3

使用javascript数组本机函数的解决方案：

var invalidAccounts = newAccounts.filter(function(account){ // we need to filter accounts
  return blacklist.some(function(word){ // and return those that have any of the words in the text
      return account.indexOf(word) != -1
  })
});

更多信息：Array.filter和 Array.some

Answer 4

这是小提琴： https://jsfiddle.net/swaprks/n1rkfuzh/

<强> JAVASCRIPT：

// Create our arrays
var blacklist = ["admin", "webform", "spoof"];
var newAccounts = ["admin1@google.com", "interweb@google.com", "puppy@google.com"];
var invalidAccounts = [];

for(var x = 0; x < newAccounts.length; x++){
    for(var y = 0; y < blacklist.length; y++){


          if( newAccounts[x].indexOf(blacklist[y]) > -1){
            alert(blacklist[x] + " is in the blacklist array");
            // Push the newAccounts value into the invalidAccounts array since it contains
            // a blacklist word.
            invalidAccounts.push(newAccounts[x]);
          }else{
            alert('no matches');
          }
    }
}

检查数组中的部分匹配

4 个答案: