我希望快速切换颜色以代表Connect 4计划中的赢家。我真的很难过，目前还没办法怎么做。任何帮助表示赞赏。
提前致谢。这是我的代码：
from Tkinter import *
from functools import partial
import time
top = Tk()
top.title("Juan's Zany Super Crazy Connect Four!")
turn=1
nextS=[35,36,37,38,39,40,41]
def winFound():
for f in range(0,7):
buttonList[0+f].config(state=DISABLED)
def checkWin():
for o in range (0,6):
for h in range (0,4):
if board[(35-7*o)+h].cget('bg')==board[(36-7*o)+h].cget('bg')==board[(37-7*o)+h].cget('bg')==board[(38-7*o)+h].cget('bg')!='grey80':
for q in range (0,4):
global turn
board[(35-7*o)+h].config(bg='green')
board[(36-7*o)+h].config(bg='green')
board[(37-7*o)+h].config(bg='green')
board[(38-7*o)+h].config(bg='green')
winFound()
for o in range(0,3):
for j in range(0,7):
if board[(0+7*o)+j].cget('bg')==board[(7+7*o)+j].cget('bg')==board[(14+7*o)+j].cget('bg')==board[(21+7*o)+j].cget('bg')!='grey80':
for q in range (0,4):
global turn
board[(0+7*o)+j].config(bg='green')
board[(7+7*o)+j].config(bg='green')
board[(14+7*o)+j].config(bg='green')
board[(21+7*o)+j].config(bg='green')
winFound()
for o in range(0,4):
for x in range(0,3):
if board[35-(7*x)+o].cget('bg')==board[29-(7*x)+o].cget('bg')==board[23-(7*x)+o].cget('bg')==board[17-(7*x)+o].cget('bg')!='grey80':
for q in range (0,4):
global turn
board[35-(7*x)+o].config(bg='green')
board[29-(7*x)+o].config(bg='green')
board[23-(7*x)+o].config(bg='green')
board[17-(7*x)+o].config(bg='green')
winFound()
for o in range(0,4):
for x in range(0,3):
if board[41-(7*x)-o].cget('bg')==board[33-(7*x)-o].cget('bg')==board[25-(7*x)-o].cget('bg')==board[17-(7*x)-o].cget('bg')!='grey80':
for q in range (0,4):
global turn
board[41-(7*x)-o].config(bg='green')
board[33-(7*x)-o].config(bg='green')
board[25-(7*x)-o].config(bg='green')
board[17-(7*x)-o].config(bg='green')
winFound()
def buttonStuff(z):
global turn
if turn==1:
board[nextS[z]].config(bg='blue')
nextS[z]=nextS[z]-7
turn=turn+1
if nextS[z]<0:
buttonList[z].config(state=DISABLED)
elif turn==2:
board[nextS[z]].config(bg='red')
nextS[z]=nextS[z]-7
turn=turn-1
if nextS[z]<0:
buttonList[z].config(state=DISABLED)
checkWin()
top = Tk()
r=0
count=0
col=0
buttonList = list()
for z in range(7):
buttonList.append(Button(text=str(z), font='times 48', command=partial(buttonStuff, z)))
buttonList[-1].grid(row=r,column=col, sticky='NESW')
count+=1
col+=1
r=1
col=0
count=0
board = list()
for z in range(42):
board.append(Label(text='', font='Helvetica 15', bg='grey80'))
board[-1].grid(row=r,column=col, sticky='NESW', padx=2, pady=2, ipadx=2, ipady=25)
count+=1
col+=1
if count==7:
r=r+1
count=0
col=0
top.mainloop()
答案 0 :(得分：1)
有许多使用tkinter进行动画的例子。基本思想是编写一个执行一帧动画的函数，然后使用after来安排下一帧。
这是一个非常简单的函数实现，它会使窗口小部件闪烁两秒钟。必须让小部件闪烁，闪烁多少次，以及两种颜色。它将在颜色之间交替，每隔100毫秒调用一次。
def blink(widget, count, color1, color2):
current_color = widget.cget("background")
color = color2 if current_color == color1 else color1
widget.configure(background=color)
if count > 1:
widget.after(100, blink, widget, count-1, color1, color2)
以下是如何使用它的示例，在默认背景和绿色之间切换：
root = tk.Tk()
label = tk.Label(root, text="Winner!")
label.pack()
blink(label, 20, "green", label.cget("background"))
root.mainloop()
这种功能正是类和继承的好处：获取现有对象并添加新功能。在这种情况下，我们要向标签添加blink方法。
以下类添加了blink方法，但其他方法与标准Label完全相同：
class BlinkableLabel(tk.Label):
def blink(self, color):
self._original_color = self.cget("background")
self._blink_color = color
print("calling blinker...")
self._blinker()
def _blinker(self, count=20):
current_color = self.cget("background")
if current_color == self._blink_color:
self.configure(background=self._original_color)
else:
self.configure(background=self._blink_color)
if count > 0:
self.after(100, self._blinker, count-1)
else:
self.configure(background=self._original_color)
以下是如何使用它的示例：
root = tk.Tk()
label1 = BlinkableLabel(root, text="winner!")
label2 = BlinkableLabel(root, text="Danger!")
label1.pack(padx=20, pady=20)
label2.pack(padx=20, pady=20)
label1.blink("green")
label2.blink("red")
root.mainloop()