我想从CoreData中删除自定义单元格中UILabel提供的单个字符串。所以从tableview中删除一行是行不通的。
另外,我想检查特定字符串是否在CoreData值中。
例如:
我有一个名为“Favorites”的实体,其名为“services”的属性带有我插入的名为“micro”的字符串。我想删除“微”。另外,我想检查“微”(例如)是否来自属性“services”和实体“Favorites”的字符串。
我试过这个:
1
let serString = servico.text
let appDel:AppDelegate = UIApplication.sharedApplication().delegate as! AppDelegate
let contexto:NSManagedObjectContext = appDel.managedObjectContext
let entidade = NSEntityDescription.entityForName("Favorites", inManagedObjectContext: contexto)
let pedido = NSFetchRequest(entityName: "Favorites")
pedido.predicate = NSPredicate(format: "service = %@", serString!)
let p:Favorites? = Favorites(entity: entidade!, insertIntoManagedObjectContext: contexto)
contexto.deleteObject(p!)
...但它没有删除字符串“serString”
2。 试过这个:
var request : NSFetchRequest = NSFetchRequest(entityName: "Favorites");
request.predicate = NSPredicate(format: "services = %s", "micro")
let results : [NSManagedObject] = context.executeFetchRequest(request, error: &error)
if (results.count > 0) {
print("exists") }
else {
//Doesn't exist
}
...但是在“& error”中出现错误,说“使用未解析的标识符'错误'”
图2(b)。
也尝试了这个,但崩溃了输出提供的应用
“打印错误说明: (NSError)错误=“超出范围”
(lldb)“
let request : NSFetchRequest = NSFetchRequest(entityName: "Favorites");
request.predicate = NSPredicate(format: "services = %s", "micro")
do {
let results : [NSManagedObject] = try context.executeFetchRequest(request) as! [Favorites]
if (results.count > 0) {
print("exists") }
else {
//Doesn't exist
}
// success ...
} catch let error as NSError {
// failure
print("Fetch failed: \(error.localizedDescription)")
}
更新
此代码最终用于删除字符串:
let favoriteFetchRequest = NSFetchRequest(entityName:"Favorites")
let predicate = NSPredicate(format: "services = %@", serv)
favoriteFetchRequest.predicate = predicate
do {
let fetchedEntities = try context.executeFetchRequest(favoriteFetchRequest) as! [NSManagedObject]
for entity in fetchedEntities {
context.deleteObject(entity)
try context.save()
}
} catch let error as NSError {
print("Fetch failed: \(error.localizedDescription)")
}
有关2的任何帮助吗?
答案 0 :(得分:0)
1。我认为你需要这样的东西:
str = ""s + c;