我的控制台出现错误,其中显示" Firebase未定义"。
1。看起来像这样" base"代码避免在另一个之前加载。
EDIT无法将脚本放入标题中,因此需要这样做
var script = document.createElement("script");
script.type = "text/javascript";
script.src = "https://cdn.firebase.com/v0/firebase.js";
document.head.appendChild(script);
2。所以我需要以某种方式推迟这些。我将如何实现这一目标?
var myDataRef = new Firebase('https://eloquatest.firebaseio.com/');
myDataRef.on('child_added', function(snapshot) {
var post = snapshot.val();
});
function submitPost(e) {
var myDataRef = new Firebase('https://eloquatest.firebaseio.com/');
var name = $('#field0').val();
myDataRef.push({name: name});
$('#field0').val('');
}
第3。我试图把它放在$( document ).ready(function()
内但是没有用。
链接:https://learn.jquery.com/using-jquery-core/document-ready/
答案 0 :(得分:1)
以这种方式使用var s = Snap("#svg-snap .svg-design-i");
var line = s.select("#se-line");
var box = line.getBBox();
var cx = box.width/2+box.x;
var cy = box.height/2+box.y;
line.animate({ transform: "r15," + cx + ',' + cy}, 1000, mina.easeIn, function() {
line.animate({ transform: "r0," + cx + ',' + cy}, 1000, mina.easeIn, function() {
animSnap();
})
});
的{{1}}方法:
onload
答案 1 :(得分:1)
您要找的是onload
事件:
var script = document.createElement("script");
document.head.appendChild(script);
script.onload = function() {
var myDataRef = new Firebase('https://eloquatest.firebaseio.com/');
myDataRef.on('child_added', function(snapshot) {
var post = snapshot.val();
});
function submitPost(e) {
var myDataRef = new Firebase('https://eloquatest.firebaseio.com/');
var name = $('#field0').val();
myDataRef.push({name: name});
$('#field0').val('');
}
};
script.type = "text/javascript";
script.src = "https://cdn.firebase.com/v0/firebase.js";
请注意,根据此SO帖子[Trying to fire the onload event on script tag],这些操作(调用appendChild
,设置src
和onload
)的顺序很重要。避风港检查一下。
此外,由于您使用的是jQuery,您可能需要查看getScript
函数:http://api.jquery.com/jQuery.getScript/