我有一个如下所示的数组,因为你可以看到最后一个数组[adad]值是空白的,我怎么能写一个if语句来判断它是否为空。
Array
(
[K] => Array
(
[0] => mabel__chan
[1] => mabel chan
)
[B] => Array
(
[0] => kieron br
)
[C] => Array
(
[0] => a br
[1] => a
)
[adad] => Array
(
[0] =>
)
)
我尝试过这样做
if (count(array_filter($array)) == 0) {}
伪码
if(array[key] == blank) {
echo "is blank";
} else {
echo "isn't blank";
}
** PHP脚本这是我从mongoDB获取数据的方法* 当我使用回声时,下面的答案正常工作,但现在当我试图推入新阵列时,它已经破坏了某个地方,我再也没有数据了。
$col = "A" . $user->agencyID;
$db = $m->rules;
$collection = $db->$col;
$id = $_POST['ruleID'];
$search = array(
'_id' => new MongoId($id)
);
$cursor = $collection->find($search);
$validTagsArray = array();
$validArray = array();
foreach ($cursor as $key => $value) {
$temp = array_walk($array, function($v, $k) {
if (count(array_filter($v)) === 0) {
foreach ($value['AutoFix'] as $keyTwo => $valTwo) {
$x = 0;
$validTagsArray['data'][] = array($keyTwo, $x);
}
} else {
foreach ($value['AutoFix'] as $keyTwo => $valTwo) {
$x = 0;
foreach ($valTwo as $key => $value) {
$x++;
}
$validTagsArray['data'][] = array($keyTwo, $x);
}
}
});
}
echo json_encode($validTagsArray);
答案 0 :(得分:2)
你可以试试这个 -
dbHelper = new DBHelper(getApplicationContext());
SQLiteDatabase db = dbHelper.getReadableDatabase();
Cursor cursor = db.rawQuery("select * from centuaryTbl where email='"+email+"'",null);
if (cursor.moveToFirst())
{
do
{
String s1 = cursor.getString(cursor.getColumnIndex("s1"));
String s2 = cursor.getString(cursor.getColumnIndex("s2"));
String s3 = cursor.getString(cursor.getColumnIndex("s3"));
}while (cursor.moveToNext());
}
<强>输出强>
$array = array
(
'K' => array('0' => 'mabel__chan','1' => 'mabel chan'),
'B' => array('0' => 'kieron br'),
'C' => array('0' => 'a br', '1' => 'a'),
'adad' => array('0' => '')
);
$temp = array_walk($array, function($v, $k) {
if(count(array_filter($v)) === 0) { // check the count of non-empty elements in the sub array
echo $k . ' is empty';
}
});
答案 1 :(得分:0)
您可以写为:
if([adad][0]== " ")
{
}
你也可以试试这个:
foreach($array as $key=>$value){
if(empty($value))
echo "empty";
}