我正在编写一个可以通过esp8266将数据发送到arduino板的Android应用程序。我一直在关注附加的代码,但我不知道如何将HttpClient更改为HttpURLConnection
/**
* Description: Send an HTTP Get request to a specified ip address and port.
* Also send a parameter "parameterName" with the value of "parameterValue".
* @param parameterValue the pin number to toggle
* @param ipAddress the ip address to send the request to
* @param portNumber the port number of the ip address
* @param parameterName
* @return The ip address' reply text, or an ERROR message is it fails to receive one
*/
public String sendRequest(String parameterValue, String ipAddress, String portNumber, String parameterName) {
String serverResponse = "ERROR";
try {
HttpClient httpclient = new DefaultHttpClient(); // create an HTTP client
// define the URL e.g. http://myIpaddress:myport/?pin=13 (to toggle pin 13 for example)
URI website = new URI("http://"+ipAddress+":"+portNumber+"/?"+parameterName+"="+parameterValue);
HttpGet getRequest = new HttpGet(); // create an HTTP GET object
getRequest.setURI(website); // set the URL of the GET request
HttpResponse response = httpclient.execute(getRequest); // execute the request
// get the ip address server's reply
InputStream content = null;
content = response.getEntity().getContent();
BufferedReader in = new BufferedReader(new InputStreamReader(
content
));
serverResponse = in.readLine();
// Close the connection
content.close();
} catch (ClientProtocolException e) {
// HTTP error
serverResponse = e.getMessage();
e.printStackTrace();
} catch (IOException e) {
// IO error
serverResponse = e.getMessage();
e.printStackTrace();
} catch (URISyntaxException e) {
// URL syntax error
serverResponse = e.getMessage();
e.printStackTrace();
}
// return the server's reply/response text
return serverResponse;
}