Question

我需要将以下XML反序列化为C#

中的对象

XML：

<rdlt version="1.5" xmlns:rdlt="http://www.rdlt.org" xmlns="http://www.rdlt.org">
    <created>2016-02-18T15:36:29.326+00:00</created>
    <updated>2016-02-18T15:36:29.326+00:00</updated>
</rdlt>

对象：

[XmlType(AnonymousType = true)]
[XmlRoot(Namespace = "http://www.rdml.org")]
public class Container
{
    [XmlElement(Namespace = "http://www.rdml.org")]
    public DateTime created { get; set; }
    [XmlElement(Namespace = "http://www.rdml.org")]
    public DateTime updated { get; set; }
}

反序列化：

var reader = XmlReader.Create(@"C:\tmp\test.xml");
var serializer = new DataContractSerializer(typeof(Container));
var object = serializer.ReadObject(reader);

我收到以下错误，表明元素和架构不匹配：

 Additional information: Error in line 1 position 2. Expecting element  
'Container' from namespace 'http://schemas.datacontract.org/2004/07/ConsoleApplication1'.. 
Encountered 'Element'  with name 'rdlt', namespace 'http://www.rdlt.org'.

已经尝试过

将rdlt名称添加到根
reader.MoveToContent（）;
的XmlReader

Answer 1

试试这个...这段代码使用XmlSerializer .....

Usings .....

action [:create]

类.....

using System;
using System.IO;
using System.Text;
using System.Xml;
using System.Xml.Serialization;

代码.....

[XmlRoot(ElementName = "rdlt", Namespace = "http://www.rdlt.org")]
public class Container
{
    [XmlElement(ElementName = "created", Namespace = "http://www.rdlt.org")]
    public string Created { get; set; }
    [XmlElement(ElementName = "updated", Namespace = "http://www.rdlt.org")]
    public string Updated { get; set; }
}

您的XML

class Program
{
    static void Main(string[] args)
    {
        string strXML = File.ReadAllText("xml.xml");
        byte[] bufXML = ASCIIEncoding.UTF8.GetBytes(strXML);
        MemoryStream ms1 = new MemoryStream(bufXML);

        // Deserialize to object
        XmlSerializer serializer = new XmlSerializer(typeof(Container));
        try
        {
            using (XmlReader reader = new XmlTextReader(ms1))
            {
                Container deserializedXML = (Container)serializer.Deserialize(reader);

            }// put a break point here and mouse-over deserializedXML ….
        }
        catch (Exception ex)
        {
            throw;
        }
    }
}

我正在从名为xml.xml的应用程序构建文件夹中的文件中读取XML到一个字符串...您需要从其他地方获取XML字符串或创建xml.xml文件并保存XML上面的代码工作

Answer 2

有几个问题：

object不是本地变量的有效名称（请确保下次使用真实代码），它可以是@object;
有效xml以?xml标记开头（例如<?xml version="1.0" ?>）;
version是?xml的一部分，如果您想在根元素中使用 xml属性 version="1.5"，那么您就遇到了麻烦;

如果您必须反序列化那个确切的xml，那么您唯一的选择就是手动反序列化，例如：使用linq-to-xml：

var xml = XDocument.Load(@"C:\tmp\test.xml");
string version = xml.Root.Attribute("version").Value;
string space = "http://www.rdlt.org";
var obj = new Container()
{
    created = DateTime.Parse(xml.Root.Element(XName.Get("created", space)).Value),
    updated = DateTime.Parse(xml.Root.Element(XName.Get("updated", space)).Value),
};

如果您省略version并且可以添加?xml代码，则DataSerializer应该有效。

E.g。这个有效 xml：

<?xml version="1.0" encoding="utf-8"?>
<rdlt xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.rdml.org">
    <created>0001-01-01T00:00:00</created>
    <updated>0001-01-01T00:00:00</updated>
</rdlt>

可以使用以下命令反序列化：

[DataContract(Name = "rdlt", Namespace = "http://www.rdml.org")]
public class Container
{
    [DataMember]
    public DateTime created { get; set; }
    [DataMember]
    public DateTime updated { get; set; }
}

// deserialize (using your code!)
var reader = XmlReader.Create(@"C:\tmp\test.xml");
var serializer = new DataContractSerializer(typeof(Container));
var obj = serializer.ReadObject(reader);

使用不同的声明反序列化xml

2 个答案: