我有桌子:
我在php中做一个项目,需要为特定用户(通过他的用户名)进行SQL查询 - 需要知道用户旅行历史表中Trip_Num的Trip_Type。
附上我的表格:
行程
用户的旅行历史
更新: 我需要对Trip_type中的每个值进行计数。我的意思是我想看到"步行" - 4次出现,"自行车" - 3次出现,这很好吗?.......................................... .................................选择Trips_History。*,Trips.Trip_Type,COUNT(Trip_Type)AS Trip_Type_occurrence FROM Trips历史INNER JOIN Trips on Trips_History.Trip_Num = Trips.Trip_Num GROUP BY Trip_Type ORDER BY Trip_Type_occurrence DESC -
答案 0 :(得分:0)
一个简单的JOIN
会:
SELECT
th.*,
t.Trip_Type
FROM Trip_History AS th
INNER JOIN Trips AS t
ON t.Trip_Num = th.Trip_Num
答案 1 :(得分:0)
试试这个:
select Trips_History.*,COUNT(Trips.Trip_Type) AS Trip_Type_occurrence FROM Trips_History INNER JOIN Trips on Trips_History.Trip_Num = Trips.Trip_Num GROUP BY Trip_Type ORDER BY Trip_Type_occurrence DESC
答案 2 :(得分:0)
试试这个
select t2.traveller_username,t1.Trip_Type from
trips as t1 inner join trips_history as t2 on t1.Trip_num=t2.trip_num
答案 3 :(得分:0)
尝试,
SELECT t.Trip_Type, u.Trip_Num from trips at t
JOIN user_trips_history ON u.Trip_Num = t.Trip_Num
WHERE u.Traveller_Username = 'username';
答案 4 :(得分:0)
尝试做:
SELECT t.Trip_Type, u.Trip_Num FROM trips as t
JOIN user_trips_history as u ON t.Trip_Num=u.Trip_Num
WHERE u.Traveller_Username = 'USERNAME';
答案 5 :(得分:0)
你可以试试这个 -
SELECT users_trip_history.trip_num, trips.trip_type, COUNT(trips.trip_type) AS trip_occurences
FROM users_trip_history
INNER JOIN trips
ON users_trip_history.trip_num = trips.trip_num
WHERE users_trip_history.traveler_username = "name"
GRUOP BY trip_num;