Question

import pygame
import time
import random

pygame.init()

white = (255,255,255)
black = (0,0,0)
red = (255,0,0)
green = (0,155,0)
blue = (0, 0, 200)

#img = pygame.image.load("rectangle.png")

displayW = 500
displayH = 500

display = pygame.display.set_mode((displayW, displayH))
pygame.display.update()

clock = pygame.time.Clock()

rectSize = 40
obstacleSize = 30

FPS = 30

def left(obstaclex,obstacley):
    pygame.draw.rect(display, blue, [0, obstacley, rectSize, rectSize])

def right(rectx,recty):
    pygame.draw.rect(display, blue, [rectx, recty, rectSize, rectSize])

def middleL(obstaclex, obstacley):
    obstacleSize = -230
    obstaclex = 500
    pygame.draw.rect(display, red, [obstaclex,obstacley, obstacleSize, rectSize])

def middleR(obstaclex, obstacley):
    obstacleSize = 210
    obstaclex = 0
    #display.blit(img, (obstaclex, obstacley))
    pygame.draw.rect(display, red, [obstaclex, obstacley, obstacleSize, 40])
def middle(obstaclex, obstacley):

    middleL(obstaclex, obstacley)
    middleR(obstaclex, obstacley)



def gameLoop():
    gameExit = False
    gameOver = False

    obstacley = 10
    obstaclex = 1

    rectx = 220
    recty = 400

    rect1 = (rectx, recty, rectSize, rectSize)


    obstacleRectX = 0
    obstacleRectY = 20

    obstacleChangeX = 0
    obstaleChageY = 0
    randrect = random.randrange(0,4)

    myRight = rectx + rectSize
    myLeft = rectx
    myTop = recty
    myBottom = recty + rectSize

    otherRight = obstaclex + obstacleSize
    otherLeft = obstaclex
    otherTop = obstacley
    otherBottom = obstacley + rectSize

    randObstacle = random.randrange(0,2)

    while not gameExit:

        pressed = pygame.key.get_pressed()

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                gameExit = True

        display.fill(black)
        pygame.draw.rect(display, blue, [rectx, recty, rectSize, rectSize])

        if pressed[pygame.K_RIGHT]:
            display.fill(black)
            rectx = displayW/2 + 70 + rectSize
            right(rectx,recty)

        if pressed[pygame.K_LEFT]:
            display.fill(black)
            rectx = displayW/2 - 170
            left(rectx,recty)

        if pressed[pygame.K_LEFT] and pressed[pygame.K_RIGHT]:
            display.fill(black)
            rectx = displayW/2 + 100
            right(rectx,recty)
            rectx = displayW/2 - 170
            left(rectx,recty)

        else:
            display.fill(black)
            pygame.draw.rect(display, blue, [rectx, recty, rectSize, rectSize])
            rectx = displayW/2 - 30

##        if randObstacle == 0:
##            
##            middleL(obstaclex, obstacley)
##            obstacley += 5
##            randObstacle = random.randrange(0,2)
##        elif randObstacle == 1:
##            
##            middleR(obstaclex, obstacley)
##            obstacley += 5
##            randObstacle = random.randrange(0,2)
##        elif randObstacle == 2:
##            
##            middle(obstaclex, obstacley)
##            obstacley += 5
##            randObstacle = random.randrange(0,2)


        middleR(obstaclex, obstacley)
        obstacley += 5
        collision = True
        if ((myRight < otherLeft) and (myLeft > otherRight) and (myBottom < otherTop) and (myTop > otherBottom)):
            # i replaced the OR's with AND's
            collision = False
            print collision


        pygame.display.update()

        clock.tick(FPS)
    pygame.quit()
    quit()
gameLoop()

我试图让一个矩形与朝向它的矩形相撞，但是我似乎无法让它们正确地碰撞。我想用if语句来做这件事，而不是sprite.collide()。

这段代码不是很精致，我会修复它，但暂时帮助我理解代码。

**这是编辑后的代码**

Answer 1

当你开始做这种事情的方法是制作8个变量（这只是伪代码）

myRight = x + width
myLeft = x
myTop = y
myBottom = y + height

otherRight = x + width
otherLeft = x
otherTop = y
otherBottom = y + height

最简单的方法是从碰撞开始并尝试反驳它

collision = True

if ((myRight < otherLeft) or (myLeft > otherRight) or (myBottom < otherTop) or (myTop > otherBottom)):
    collision = False

你必须自己实现这个，但是当我开始使用八个变量myRight，myLeft等时我发现它很有用，因为它们可以帮助你理解所有x +宽度实际意味着什么

好的，我不会在这里发布整个代码，因为它会使这个评论很长。我删除了这个动作和很多无关紧要的东西。你需要先计算一切，然后画出来。

这是你的游戏，直到工作碰撞的裸骨： http://pastebin.com/P0HyPGY0

pygame：当另一个接触

1 个答案: