我有以下问题。我想在数组中找到这些值，当不是true或不存在时，删除数组
示例：
$array =array(
array(
'menu' => 'hide',
'label' => 'Notice',
'class' => 'menu-icon fa fa-newspaper-o',
'route' => 'notice',
'action'=> 'index',
),
array(
'label' => 'Nivel',
'class' => 'menu-icon fa fa-file-text-o',
'uri' => '#',
'pages' => array(
array(
'label' => 'Tur',
'pages' => array(
array(
'menu' => 'hide',
'label' => 'Content',
'route' => 'g7t',
'action' => 'index',
'params' => array(
'nivel' => 'gdfa',
),
),
array(
'menu' => 'hide',
'label' => 'Plan',
'route' => 'plan',
'action' => 'index',
'params' => array(
'nivel' => 'gdr',
),
),
array(
'menu' => 'hide',
'label' => 'Lan',
'action' => 'index',
'params' => array(
'nivel' => 'bcn',
),
'pages' => array(
array(
'menu' => 'hide',
'label' => 'lan2',
'route' => 'lan2',
'action' => 'list',
'params' => array(
'nivel' => 'gr',
),
),
),
),
array(
'menu' => 'hide',
'label' => 'notes',
'route' => 'notes',
'action' => 'index',
'params' => array(
'nivel' => 'gran',
),
),
),
),
array(
'label' => 'Disp',
'route' => '/',
),
),
),
);
现在我想把这些位置放在数组中：
$arrayfilter= [
'Content' => true,
'Disp' => false,
'lan2' => true,
'Plan' => false,
'notes' => true,
'Nivel' => true,
'Lan' => true,
];
现在就是那样
array(
array(
'label' => 'Nivel',
'class' => 'menu-icon fa fa-file-text-o',
'uri' => '#',
'pages' => array(
array(
'label' => 'Tur',
'pages' => array(
array(
'menu' => 'hide',
'label' => 'Content',
'route' => 'g7t',
'action' => 'index',
'params' => array(
'nivel' => 'gdfa',
),
),
array(
'menu' => 'hide',
'label' => 'Lan',
'action' => 'index',
'params' => array(
'nivel' => 'bcn',
),
'pages' => array(
array(
'menu' => 'hide',
'label' => 'lan2',
'route' => 'lan2',
'action' => 'list',
'params' => array(
'nivel' => 'gr',
),
),
),
),
array(
'menu' => 'hide',
'label' => 'notes',
'route' => 'notes',
'action' => 'index',
'params' => array(
'nivel' => 'gran',
),
),
),
),
),
));
答案 0 :(得分：1)
有一些空闲时间，所以我创建了一个循环..
一个不那么干净的解决方案，我不推荐它，但这可以根据你上面的输出工作。
foreach($array as $key1 => $levelOne) {
echo $key1."<br/>";
if(is_array($levelOne)) {
foreach($levelOne as $key2 => $levelTwo) {
echo "leveloneLoop ".$key2."<br/>";
if( $key2 == "label" && ((array_key_exists($levelOne['label'],$arrayfilter) && !$arrayfilter[$levelOne['label']])
|| !array_key_exists($levelOne['label'],$arrayfilter)) ) {
echo "delete array['".$key1."']<br/>";
unset($array[$key1]);
}
// loop to $pages ($pages, $route)
foreach($levelTwo as $key3 => $levelThree) {
foreach($levelThree as $key4 => $levelFour) {
echo "levelThreeLoop ".$key4."<br/>";
if( $key4 == "label" && ((array_key_exists($levelThree['label'],$arrayfilter) && !$arrayfilter[$levelThree['label']])
|| !array_key_exists($levelThree['label'],$arrayfilter)) ) {
echo "delete array['".$key1."']['".$key2."']['".$key3."']['".$key4."']<br/>";
unset($array[$key1][$key2][$key3]);
}
foreach($levelFour as $key5 => $levelFive) {
foreach($levelFive as $key6 => $levelSix) {
if( $key6 == "label" && ((array_key_exists($levelFive['label'],$arrayfilter) && !$arrayfilter[$levelFive['label']])
|| !array_key_exists($levelFive['label'],$arrayfilter)) ) {
echo "delete array['".$key1."']['".$key2."']['".$key3."']['".$key4."']['".$key5."']<br/>";
unset($array[$key1][$key2][$key3][$key4][$key5]);
}
}
}
}
}
}
}
}
注意到您还没有在过滤器上添加Tur，所以我添加了它。
$arrayfilter= [
'Content' => true,
'Disp' => false,
'lan2' => true,
'Plan' => false,
'notes' => true,
'Nivel' => true,
'Lan' => true,
'Tur' => true
];
如果你想更深入，那么只需添加一个循环。
答案 1 :(得分：0)
I suggest starting with a function that accepts an Array as its argument, looping through the elements of this array, and recursively calls itself in case its required to go one level deeper in the tree (i.e. you have 'pages' sub-array), passing the element by reference. If its not required to go deeper, just check the 'leaf' node match the filter criteria and unset() it in case it doesn't.