Spring REST总是返回404

Question

我使用spring mvc创建一个rest Web服务。但是，我总是得到404.我不知道哪里出错了。

这是我的初始化程序：

    //gestures  
    let gesture_tap = UITapGestureRecognizer(target: self, action: #selector(ComponentDetailViewController.ctrl_tapped(_:event:)));
    let gesture_pinch = UIPinchGestureRecognizer(target: self, action: #selector(ComponentDetailViewController.ctrl_pinched(_:event:)));
    let gesture_swipe = UISwipeGestureRecognizer(target:self, action: #selector(ComponentDetailViewController.ctrl_swiped(_:event:)));
    let gesture_longPress = UILongPressGestureRecognizer(target: self, action: #selector(ComponentDetailViewController.ctrl_longPressed(_:event:)));
    let gesture_rotate = UIRotationGestureRecognizer(target:self,action: #selector(ComponentDetailViewController.ctrl_rotated(_:event:)));
    let gesture_pan = UIPanGestureRecognizer(target:self, action: #selector(ComponentDetailViewController.ctrl_panned(_:event:)));

    let ctrl = component?.control;

    ctrl!.addGestureRecognizer(gesture_tap);
    ctrl!.addGestureRecognizer(gesture_pinch);
    ctrl!.addGestureRecognizer(gesture_swipe);
    ctrl!.addGestureRecognizer(gesture_longPress);
    ctrl!.addGestureRecognizer(gesture_rotate);
    ctrl!.addGestureRecognizer(gesture_pan);

    gesture_tap.delegate = self;
    gesture_pinch.delegate = self;
    gesture_swipe.delegate = self;
    gesture_longPress.delegate = self;
    gesture_rotate.delegate = self;
    gesture_pan.delegate = self;


    component?.control = ctrl as? UIView;

    //component?.control!.userInteractionEnabled = true;
    //component?.control!.addGestureRecognizer(tap);
    viewDisplayComponent.addSubview((component?.control)! as! UIView);

}


//Gesture methods
func ctrl_tapped(ctrl: AnyObject, event:UIEvent){
    setMessage("TO_tapped");
}
func ctrl_pinched(ctrl: AnyObject, event:UIEvent){
    setMessage("TO_pinchedWithArgs")
}
func ctrl_swiped(ctrl: AnyObject, event:UIEvent){
    setMessage("TO_swipedWithArgs");
}
func ctrl_longPressed(ctrl: AnyObject, event:UIEvent){
    setMessage("TO_longPressedWithArgs");
}
func ctrl_rotated(ctrl: AnyObject, event:UIEvent){
    //logTextView.text += "Rotated";
}
func ctrl_panned(ctrl: AnyObject, event:UIEvent){
    setMessage("TO_pannedWithArgs");
}

这是我的Webconfig：

public class Initializer extends AbstractAnnotationConfigDispatcherServletInitializer {

@Override
protected Class<?>[] getRootConfigClasses() {
    // TODO Auto-generated method stub
    return new Class<?>[] { RootConfig.class };
}

@Override
protected Class<?>[] getServletConfigClasses() {
    // TODO Auto-generated method stub
    return new Class<?>[] { WebConfig.class };
}

@Override
protected String[] getServletMappings() {
    // TODO Auto-generated method stub
        return new String[] { "/" };
    }

}

这是我的休息服务器文件：

@Configuration
@EnableWebMvc
@ComponentScan("com.jh.dummy.web")
public class WebConfig extends WebMvcConfigurerAdapter {
    @Bean
    public ViewResolver viewResolver() {
        InternalResourceViewResolver viewResovler = new InternalResourceViewResolver();
        viewResovler.setPrefix("/");
        viewResovler.setSuffix(".html");
        viewResovler.setExposeContextBeansAsAttributes(true);
        return viewResovler;
    }

    public void configureDefaultServletHandling(DefaultServletHandlerConfigurer configurer) {
        configurer.enable();
    }

}

以下是请求：

当我使用卷曲测试时，我总是得到404.我找不到哪里出错了。有什么想法吗？

Answer 1

我解决了这个问题。事实证明我需要在url中添加/ dummy /。因此，网址将是＆＃34; localhost：8080 / dummy / v1 / position / v1＆＃34;。但在我的其他项目案例中，我不需要将项目名称添加到虚拟项目中。这次我仍然不知道为什么我需要这样做。当我发现时，我会告诉你那个人。