这是我需要排序的HTML div:
<div id="divtosort">
<div class="datasort" data-order="2">2</div>
<div class="datasort" data-order="4">4</div>
<div class="datasort" data-order="1">1</div>
<div class="datasort" data-order="3">3</div>
</div>
我正在使用此功能对div进行排序:
function getSorted(selector, attrName) {
return $($(selector).toArray().sort(function(a, b){
var aVal = parseInt(a.getAttribute(attrName)),
bVal = parseInt(b.getAttribute(attrName));
return aVal - bVal;
}));
}
当我将此行输入控制台时:
getSorted('.datasort', 'data-order')
我得到了这个结果:
[ <div class="datasort" data-order="1">1</div>, <div class="datasort" data-order="2">2</div>, <div class="datasort" data-order="3">3</div>, <div class="datasort" data-order="4">4</div>]
问题是,如何将此结果转换为实际的HTML,我可以用?
替换现有的HTML答案 0 :(得分:2)
问题是,如何将此结果转换为实际的HTML,我可以用?
替换现有的HTML
你已经拥有了。在这个例子中,我使用的是jQuery的.html
函数,它将替换它所调用的节点的HTML内容:
function getSorted(selector, attrName) {
return $($(selector).toArray().sort(function(a, b){
var aVal = parseInt(a.getAttribute(attrName)),
bVal = parseInt(b.getAttribute(attrName));
return aVal - bVal;
}));
}
var sorted = getSorted('.datasort', 'data-order');
$('#divtosort').html(sorted);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="divtosort">
<div class="datasort" data-order="2">2</div>
<div class="datasort" data-order="4">4</div>
<div class="datasort" data-order="1">1</div>
<div class="datasort" data-order="3">3</div>
</div>
答案 1 :(得分:0)
reactivemongo.core.errors.ConnectionNotInitialized: MongoError['Connection is missing metadata (like protocol version, etc.) The connection pool is probably being initialized.']
at reactivemongo.core.errors.ConnectionNotInitialized$.MissingMetadata(errors.scala:71)
at reactivemongo.api.collections.GenericCollection$$anonfun$insert$1.apply(genericcollection.scala:338)
at reactivemongo.api.collections.GenericCollection$$anonfun$insert$1.apply(genericcollection.scala:314)
at scala.concurrent.impl.Future$PromiseCompletingRunnable.liftedTree1$1(Future.scala:24)
at scala.concurrent.impl.Future$PromiseCompletingRunnable.run(Future.scala:24)
at scala.concurrent.impl.ExecutionContextImpl$AdaptedForkJoinTask.exec(ExecutionContextImpl.scala:121)
at scala.concurrent.forkjoin.ForkJoinTask.doExec(ForkJoinTask.java:260)
at scala.concurrent.forkjoin.ForkJoinPool$WorkQueue.pollAndExecAll(ForkJoinPool.java:1253)
at scala.concurrent.forkjoin.ForkJoinPool$WorkQueue.runTask(ForkJoinPool.java:1346)
at scala.concurrent.forkjoin.ForkJoinPool.runWorker(ForkJoinPool.java:1979)
at scala.concurrent.forkjoin.ForkJoinWorkerThread.run(ForkJoinWorkerThread.java:107)
<div id="divtosort">
<div class="datasort" data-order="2">2</div>
<div class="datasort" data-order="4">4</div>
<div class="datasort" data-order="1">1</div>
<div class="datasort" data-order="3">3</div>
</div>
答案 2 :(得分:-1)
var $sordedElemets = getSorted('.datasort', 'data-order');
$("#divtosort").append( $sordedElemets );
<强> jsBin demo 强>
答案 3 :(得分:-1)
尝试将getSorted('.datasort', 'data-order')
的结果存储在变量中
然后清空ID为divtosort
的div,之后将sortedList
附加到div。
代码看起来有点像这样 -
var sortedList = getSorted('.datasort', 'data-order');
$('#divtosort').empty();
$('#divtosort').append(sortedList);