我尝试使用express.Router()获取可选的URL参数,但它无效。
如果我使用app.get,它工作正常:
app.get('/videos/:category', function(req, res){
// localhost:9876/videos/music
debug(req.params); // This is working as expected
});
唯一的问题是当我尝试使用express.Router()时这样使用。 我试过这样的事:
app.js:
var express = require('express');
var app = express();
var videos = require('./routes/videos');
app.use('/videos/:category', videos);
路由/ videos.js:
var express = require('express');
var router = express.Router();
router.get('/:category', function(req, res){
debug(req.params, req.params.category); // req.params is empty {}
});
module.exports = router;
我也尝试过这样:
router.get('/', function(req, res){
debug(req.params, req.params.category); // req.params is empty {}
});
如何正确解决这个问题?感谢。
答案 0 :(得分:2)
在你的两种解决方案中,你都走错了路。在第一种情况下,它是/videos/:category/:category
,在第二种情况下是/videos/:category/
。您需要将参数移至router.js router.get
并将其从app.js app.use
中删除:
<强> app.js:强>
var express = require('express');
var app = express();
var videos = require('./routes/videos');
app.use('/videos', videos);
<强>路由/ videos.js:强>
var express = require('express');
var router = express.Router();
router.get('/:category', function(req, res){
debug(req.params, req.params.category); // req.params is empty {}
});
module.exports = router;