我有actionPerformed
,其中一个if / else是如果用户按下“A”键,它会将文本设置为不同的。程序跳过设置文本并向下移动到下面的if语句,而不是在按“A”后设置文本。我的问题是,如何让我的程序在if语句之前设置文本?我的代码在下面,谢谢!
import javax.swing.*;
import java.awt.*;
import java.io.*;
import java.util.*;
import java.awt.event.*;
public class ATMProject extends JPanel implements ActionListener {
private JPanel mainPanel = null;
private JPanel btnPanel = null;
private JPanel userBtns = null;
private JTextArea textArea = null;
private JPanel keyPanel = null;
private JTextField numField = null;
private JPanel numpadPanel = null;
private JButton[] userButtons = null;
private JButton[] keypadButtons = null;
private String[] btnPanelbtns = { "A", "B", "C" };
private String[] numpadPanelbtns = { "7", "8", "9", "4", "5", "6", "1", "2", "3", "0", ".", "CE" };
private boolean isuserButtonPressed = false;
private boolean isAccEntered = true;
private FileReader file = null;
private String custAcc;
private String custPin;
private String userInputAcc;
private String userInputPin;
public ATMProject() {
super();
mainPanel = new JPanel();
this.setLayout(new BorderLayout());
this.add(mainPanel);
btnPanel = new JPanel();
btnPanel.setLayout(new GridLayout(3, 1));
this.add(btnPanel, BorderLayout.EAST);
textArea = new JTextArea();
this.add(textArea, BorderLayout.CENTER);
keyPanel = new JPanel();
keyPanel.setLayout(new BorderLayout());
this.add(keyPanel, BorderLayout.WEST);
numpadPanel = new JPanel();
numpadPanel.setLayout(new GridLayout(4, 3));
keyPanel.add(numpadPanel, BorderLayout.CENTER);
numField = new JTextField();
keyPanel.add(numField, BorderLayout.NORTH);
userButtons = new JButton[btnPanelbtns.length];
for (int i = 0; i < userButtons.length; i++) {
userButtons[i] = new JButton(btnPanelbtns[i]);
userButtons[i].addActionListener(this);
btnPanel.add(userButtons[i]);
}
keypadButtons = new JButton[numpadPanelbtns.length];
for (int i = 0; i < numpadPanelbtns.length; i++) {
keypadButtons[i] = new JButton(numpadPanelbtns[i]);
keypadButtons[i].addActionListener(this);
numpadPanel.add(keypadButtons[i]);
}
textArea.setText("Enter customer number: --> \nPress A when done \nA = OK");
userInputAcc = numField.getText();
// reading
try {
file = new FileReader("ConfidentialCustInfo.txt");
Scanner input = new Scanner(file);
custAcc = input.next();
custPin = input.next();
System.out.println(custAcc);
System.out.println(custPin);
input.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
}
}
@Override
public void actionPerformed(ActionEvent e) {
if (e.getActionCommand().equals("CE")) {
numField.setText("");
} else if (e.getActionCommand().equals("1")) {
numField.setText(numField.getText() + "1");
} else if (e.getActionCommand().equals("2")) {
numField.setText(numField.getText() + "2");
} else if (e.getActionCommand().equals("3")) {
numField.setText(numField.getText() + "3");
} else if (e.getActionCommand().equals("4")) {
numField.setText(numField.getText() + "4");
} else if (e.getActionCommand().equals("5")) {
numField.setText(numField.getText() + "5");
} else if (e.getActionCommand().equals("6")) {
numField.setText(numField.getText() + "6");
} else if (e.getActionCommand().equals("7")) {
numField.setText(numField.getText() + "7");
} else if (e.getActionCommand().equals("8")) {
numField.setText(numField.getText() + "8");
} else if (e.getActionCommand().equals("9")) {
numField.setText(numField.getText() + "9");
} else if (e.getActionCommand().equals("A")) {
if (numField.getText().isEmpty()) {
textArea.setText("error");
} else {
numField.setText("");
textArea.setText("Enter PIN: \n A = OK");
userInputPin = (numField.getText());
}
}
}
public static void main(String[] args) {
MyFrame mf = new MyFrame();
}
}
答案 0 :(得分:2)
你需要给你的程序一个状态变量,它会告诉它它处于什么状态,然后允许监听器根据该状态做出不同的响应。
例如,你可以给它一个布尔变量或变量,比如
private boolean enteringAcctNumber = true;
然后在ActionListener中放置一个if块,检查此布尔值并做出相应的响应。
例如
import java.awt.BorderLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.*;
public class ATMProj2 extends JPanel {
private static final int COLS = 30;
private static final String ACCOUNT_PROMPT = "Enter Account Number";
protected static final String ENTER_PIN = "Account number accepted. Enter PIN";
protected static final String PIN_ACCEPTED = "PIN has been accepted. Have fun.";
private boolean enteringAcctNumber = true;
private JTextField textField = new JTextField(COLS);
private JTextArea textArea = new JTextArea(6, COLS);
private JButton okButton = new JButton("OK");
public ATMProj2() {
textArea.setText(ACCOUNT_PROMPT);
textArea.setFocusable(false); // so user can't mess with it
okButton.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
// test state variable, and base behavior on its state
if (enteringAcctNumber) {
textArea.setText(ENTER_PIN);
textField.setText("");
enteringAcctNumber = false; // ok now not entering account
} else {
textArea.setText(PIN_ACCEPTED);
}
}
});
JPanel btnPanel = new JPanel();
btnPanel.add(okButton);
setLayout(new BorderLayout());
add(textField, BorderLayout.PAGE_START);
add(new JScrollPane(textArea), BorderLayout.CENTER);
add(btnPanel, BorderLayout.PAGE_END);
}
private static void createAndShowGui() {
ATMProj2 mainPanel = new ATMProj2();
JFrame frame = new JFrame("ATMProj2");
frame.setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
frame.getContentPane().add(mainPanel);
frame.pack();
frame.setLocationByPlatform(true);
frame.setVisible(true);
}
public static void main(String[] args) {
SwingUtilities.invokeLater(() -> {
createAndShowGui();
});
}
}
答案 1 :(得分:2)
这是您的其他帖子的评论:
当我使用userInputAcc = numField.getText()时,我看到了它没有从JTextField()获取文本。我认为这是因为我将JTextArea的文本设置为userInputAcc并且屏幕变为空白&gt;
textArea.setText("Enter customer number: --> \nPress A when done \nA = OK");
userInputAcc = numField.getText();
当然它是空白的,因为在构建GUI时执行该语句并且用户还没有机会在文本字段中键入任何内容。执行上述语句时,框架甚至不可见。
这很容易验证。只需将您的代码更改为:
userInputAcc = numField.getText();
System.out.println( "(" + userINputAcc + ")" );
这是在为变量赋值时显示变量值的基本调试。
生成事件时,您只能从文本字段中获取文本,并且您可以编写代码来处理事件。因此userInputAcc
变量将始终为空。
另外,为什么你的代码仍然在ActionListener中有丑陋的嵌套if语句?