Question

我正在为我的角度2应用程序编写单元测试，我正在尝试测试我制作的组件。我指的是使用TypeScript和Jasmine框架以角度2编写测试用例的示例git存储库。我在示例存储库（https://github.com/juliemr/ng2-test-seed）中做了同样的事情来测试我的组件，但是我得到了以下错误。

TypeError: Cannot read property 'firstChild' of null
at Object.el (http://127.0.0.1:9090/node_modules/angular2/bundles/testing.dev.js:537:29)
at TestComponentBuilder.createAsync (http://127.0.0.1:9090/node_modules/angular2/bundles/testing.dev.js:841:28)
at eval (http://127.0.0.1:9090/app/test/search.component.specs_test.js:95:32)
at FunctionWrapper.apply (http://127.0.0.1:9090/node_modules/angular2/bundles/angular2.dev.js:327:17)
at FunctionWithParamTokens.execute (http://127.0.0.1:9090/node_modules/angular2/bundles/testing.dev.js:1947:37)
at TestInjector.execute (http://127.0.0.1:9090/node_modules/angular2/bundles/testing.dev.js:1868:17)
at Object.<anonymous> (http://127.0.0.1:9090/node_modules/angular2/bundles/testing.dev.js:2006:44)
at attemptAsync (http://127.0.0.1:9090/node_modules/jasmine-core/lib/jasmine-core/jasmine.js:1916:24)
at QueueRunner.run (http://127.0.0.1:9090/node_modules/jasmine-core/lib/jasmine-core/jasmine.js:1871:9)
at http://127.0.0.1:9090/node_modules/jasmine-core/lib/jasmine-core/jasmine.js:1898:16

我的组件是这样的：

@Component({
  selector: 'search',
  templateUrl: 'app/html/search.component.html',
  styleUrls: ['app/css/search.css'],
  providers: [SearchService,SearchUtil],
  directives: [OverviewComponent]
})
export class SearchComponent {}

我的单元测试用例如下所示：

it('should populate search suggestions UI', injectAsync([TestComponentBuilder,SearchComponent], (tcb) => {
    return tcb.createAsync(SearchComponent).then((fixture) => {
      fixture.detectChanges();
      var compiled = fixture.debugElement.nativeElement;

      compiled.querySelector('search').value('teachers');
      fixture.detectChanges();

      var compiled = fixture.debugElement.nativeElement;

      console.log(compiled.querySelector('search').value()+" = "+compiled.querySelector('.searchlist>a').length);

      expect(compiled.querySelector('.searchlist>a').length).toBeGreaterThan(1);
    });
  }));

我收到错误，在这一行 - tcb.createAsync（SearchComponent），表示该对象为空。

AngularJS 2单元测试组件与jasmine面临错误，无法读取null的属性'firstChild'

0 个答案: