Question

我试图使用一个具有3个滚动选项的ui选择器视图，但我不能吐出我按下提交按钮时选择的选项，但它只是给1,2,3这里是我的代码代码（也不要介意它的不完整警报信息

import UIKit
import Firebase

class PitcherPickerViewController: UIViewController, UIPickerViewDelegate, UIPickerViewDataSource {

var ref: Firebase!

@IBOutlet weak var picker: UIPickerView!
@IBOutlet weak var age: UILabel!
@IBOutlet weak var paragraph: UILabel!
@IBOutlet weak var playerNum: UILabel!
@IBOutlet weak var innings: UILabel!
@IBOutlet weak var topBlue: UILabel!
@IBOutlet weak var back: UIButton!
@IBAction func submit1(sender: AnyObject) {
    ref.setValue(pickerData)

}


 var pickerData: [[String]] = [[String]]()

override func viewDidLoad() {
    super.viewDidLoad()
    ref = Firebase(url: "https://baseball-pitcher-app.firebaseIO.com/")
    // Do any additional setup after loading the view.

    // Connect data:
    self.picker.delegate = self
    self.picker.dataSource = self

    // Input data into the Array:
    pickerData = [["8", "9", "10"],
        ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "30", "31", "32", "33", "34", "35", "36", "37", "38", "39", "40", "41", "42", "43", "44", "45", "46", "47", "48", "49", "50", "51", "52", "53", "54", "55", "56", "57", "58", "59", "60", "61", "62", "63", "64", "65", "66", "67", "68", "69", "70", "71", "72", "73", "74", "75", "76", "77", "78", "79", "80", "81", "82", "83", "84", "85", "86", "87", "88", "89", "91", "92", "93", "94", "95", "96", "97", "98", "99"],
        ["1", "2", "3", "4", "5", "6"]]
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}


// The number of columns of data
func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
    return 3
}

// The number of rows of data
func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
    return pickerData[component].count
}

// The data to return for the row and component (column) that's being passed in
func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
    return pickerData[component][row]
}

// Catpure the picker view selection
func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
    // This method is triggered whenever the user makes a change to the picker selection.
    // The parameter named row and component represents what was selected.
}

func displayMyAlertMessage(userMessage:String)
{
    var myAlert = UIAlertController(title: "Oh No! ", message: userMessage, preferredStyle: UIAlertControllerStyle.Alert)

    let okAction = UIAlertAction(title: "Ok", style: UIAlertActionStyle.Default, handler: nil)

    myAlert.addAction(okAction)

    self.presentViewController(myAlert, animated: true, completion: nil)
 }

}

这是卷轴的图片 ui picker image

我已经被困了差不多一个星期了，感谢你的帮助，我似乎无法想象我的生活。

Answer 1

如果你想知道3个不同组件中的选定项目，如果你编写一个方法可以分别调用选择器视图selectedRowInComponent 3个，那么它可能是最容易的，每个组件一个（传递组件值0,1和2.）

编辑：

我建议将该逻辑放在IBAction的提交按钮中。

您还可以在didSelectRow：inComponent方法中放置逻辑，该方法每次更改时都会保存所选组件，但这对于初学者来说更有效，可能会更加混乱。

如何在swift中使用多个滚动条从ui选取器视图中获取数据

1 个答案:

编辑：