Question

我想更新表系列中的一列和父表中的两列。我知道如何在sql中做到这一点。我通过查看一些示例尝试了它，如果我尝试直接在sql中更新它，但我无法使用存储过程进行更新，则它有效。

CREATE PROCEDURE prc_EditProfile(
IN inputfamilyName VARCHAR(45),
inputuserName VARCHAR(45), 
inputfamilyID INT(20),
inputparentID INT(20)
)
BEGIN
update family, parent SET family.familyName= inputfamilyName, parent.userName=inputuserName WHERE family.FamilyID=inputfamilyID AND parent.ParentID=inputfamilyID;
END

Answer 1

了解Update。

你可以这样做（测试电话）：

<?php
include "includes/db_config.php";
include "ChromePhp.php";
$post = getRealPOST();
ChromePHP::log("Array : ", $post);
$id = intval($post['Id']);
$Serie = $post['Serie'];
$Producto = $post['Producto'];
$AVL = $post['AVL'];
$UniqueId = $post['UniqueId'];
$sim = $post['sim'];
$conn = sqlsrv_connect(SV_NAME, $connectionInfo) OR die("Unable to connect to the database");
$sql = "SELECT Id,Numero from Lineas WHERE Sim= $sim";
$params = array();
$options =  array( "Scrollable" => SQLSRV_CURSOR_KEYSET );
$result = array();  
$res = sqlsrv_query($conn, $sql, $params, $options);
if(sqlsrv_num_rows($res) == 0){
    echo json_encode(array(
    'isError' => true,
    'msg' => 'No existe SIM en BD'
    ));
    ChromePHP::log("Error no rows");
    ChromePHP::log($sql);
}else if(sqlsrv_num_rows > 1){
    ChromePHP::log("Error no rows");
    echo json_encode(array(
    'isError' => true,
    'msg' => 'Multiples SIM en BD'
    ));
}else{
    $row = sqlsrv_fetch_array( $res, SQLSRV_FETCH_ASSOC);
    $telefono = $row['Numero'];
    $sql = "UPDATE producto SET Sim_Id=(SELECT Id from Lineas WHERE Sim= $sim) WHERE Id = $id"; 
    $res = sqlsrv_query($conn, $sql, $params, $options);
    echo json_encode(array(
    'isSuccess' => true,
    'Id' => $Id,
    'Serie' => $Serie,
    'UniqueId' => $UniqueId,
    'AVL' => $AVL,
    'Producto' => $Producto,
    'sim' => $sim,
    'Numero' => $telefono
    ));
    ChromePHP::log($sql);
}

function getRealPOST() {
    $pairs = explode("&", file_get_contents("php://input"));
    $vars = array();
    foreach ($pairs as $pair) {
        $nv = explode("=", $pair);
        $name = urldecode($nv[0]);
        $value = urldecode($nv[1]);
        $vars[$name] = $value;
    }
    return $vars;
}
?>

使用存储过程更新两个表

1 个答案: