我正在使用bootstrap。这是我想要显示所有列表项的表。
<table id="playlist_table" class="table table-bordered">
<caption class="text-center">PLAYLIST</caption>
<thead>
<tr>
<th>Song Name</th>
<th>Singer</th>
<th>Film</th>
</tr>
</thead>
<tbody id="palylist_table_data">
</tbody>
</table>
这是我的播放列表:
<ul id="playlist" class="hidden">
<li Src="Ek%20duje%20ke%20vaaste%20serial%20title%20song.mp3" Title="Ek Duje Ke Vasste" Singer="Unkown" Cover="Album images/ek.jpg"> Ek Duje Ke VAste
</li>
<li Src="Lak.mp3" Title="Lakshya ko HAr haal mein Paana HAi" Singer="Shankar Mahadevan" Cover="Album images/lakshya.jpg"> LAkshya
</li>
</ul>
这是我编写的Jquery代码,但我无法在表中获取任何数据。
$('.playlist li').each(function(){
var song = $(this).attr('Src');
var title = $(this).attr('Title');
var singer = $(this).attr('Singer');
var cover = $(this).attr('Cover');
$('#playlist_table_data').html('<tr>' + '<td>' + '*' + '</td>' + '<td>' + song + '</td>' + '<td>' + singer + '</td>' + '<td>' + title + '</td>' + '</tr>');
});
答案 0 :(得分:-1)
由于播放列表是ID元素,因此请使用“#”代替“。”
$('#playlist li').each(function() {...//code here});
并更改最后一行,如下所示:( append()而不是html())
$('#playlist_table_data').append('<tr>' + '<td>' + '*' + '</td>' + '<td>' + song + '</td>' + '<td>' + singer + '</td>' + '<td>' + title + '</td>' + '</tr>');