Question

我正在尝试创建一个带有字符串密码的应用程序，它所做的就是迭代所有可能的字符和数字组合，直到找到正确的密码，就像这样：

import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;

public class PasswordDetector extends AppCompatActivity {
private static final String PASSWORD = "abc123";
private Button search;
private EditText combination;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    search.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            //here I want the loop to run, untill it hits the PASSWORD
            combination.setText("combinations");
            if (combination.getText().toString().equals(PASSWORD)) {
                Toast.makeText(PasswordDetector.this, "Success", Toast.LENGTH_SHORT).show();
            }
        }
    });


}
}

我该如何接近它？

Answer 1

此类问题的最常见方法是重复排列。

unittest {
  struct S(A...) {}
  static assert(is(S!(QName!"com.example"[0..$-1]) == S!(QName!"com")));
  static assert(is(S!(QName!"com.example", QName!"mail") == S!(QName!"com.example.mail")));
  static assert(is(S!(QName!"com"[0..$-1]) == S!(QName!"")));
}

public static String[] getAllLists(String[] elements, int lengthOfList) { //initialize our returned list with the number of elements calculated above String[] allLists = new String[(int)Math.pow(elements.length, lengthOfList)]; //lists of length 1 are just the original elements if(lengthOfList == 1) return elements; else { //the recursion--get all lists of length 3, length 2, all the way up to 1 String[] allSublists = getAllLists(elements, lengthOfList - 1); //append the sublists to each element int arrayIndex = 0; for(int i = 0; i < elements.length; i++){ for(int j = 0; j < allSublists.length; j++){ //add the newly appended combination to the list allLists[arrayIndex] = elements[i] + allSublists[j]; arrayIndex++; } } return allLists; } } public static void main(String[] args){ String[] database = {"a","b","c"}; for(int i=1; i<=database.length; i++){ String[] result = getAllLists(database, i); for(int j=0; j<result.length; j++){ System.out.println(result[j]); } } }是passwd中使用的字符数组。
String[] elements是密码长度。

Check this answer

创建＆＃34;密码检测器＆＃34;对于android项目中的EditText

1 个答案: