我的数据库中有两个表，我正在尝试加入：
表格示例＆＃34;帖子＆＃34;：
id | author | title
21 | 1 | This is my post.
22 | 2 | I am another title.
23 | 3 | And yet another post.
表格示例＆＃34; usermeta＆＃34;：
meta_id | user_id | meta_key | meta_value
1 | 1 | name | John Doe
2 | 1 | zip-code | 12345
3 | 1 | status | premium
4 | 2 | name | Steve Jobs
5 | 2 | zip-code | 22499
6 | 2 | status | basic
现在经过最近几个小时的实验，我回到了我的初步查询：
SELECT * FROM posts
LEFT JOIN usermeta ON posts.author = usermeta.user_id
WHERE posts.author = 1
这给了我以下结果：
id | author | title | user_id | meta_key | meta_value |
21 | 1 | This is my post. | 1 | name | John Doe |
21 | 1 | This is my post. | 1 | zip-code | 12345 |
21 | 1 | This is my post. | 1 | status | premium |
但是我试图解决这个问题：
id | author | title | user_id | author_name | author_zip | author_status |
21 | 1 | This is my post. | 1 | John Doe | 12345 | premium |
为了达到上述结果我还能尝试什么？
谢谢！