Question

我的文件名称要更改。

示例：

Nashville.2012.SXXEXX.W.ac3
How.To.Get.Away.With.Murder.SXXEXX.W.ac3
Better.Call.Saul.SXXEXX.W.ac3
Beauty.And.The.Beast.2012.SXXEXX.W.ac3
Hawaii.Five.0.2010.SXXEXX.W.ac3

我需要转换它们：

echo Nashville2012SXXEXXW.ac3 | sed 's/[A-Z]/.&/g;s/^.//'
Nashville2012.SXX.EXX.W.ac3
echo HowToGetAwayWithMurderSXXEXXW.ac3 | sed 's/[A-Z]/.&/g;s/^.//'
How.To.Get.Away.With.Murder.SXX.EXX.W.ac3

我发现了这个：

this.login = function (username, password, rememberMe) {
if (rememberMe === undefined) rememberMe = false;
return $http.post(
  '/j_spring_security_check',
  $.param({
    j_username: username,
    j_password: password,
    j_remember: rememberMe
  }),
  {
    headers: {
      'Content-Type': 'application/x-www-form-urlencoded',
      'X-Requested-With': 'XMLHttpRequest'
    }
  }
).then(_.bind(function (response) {
  if (response.data.success === true) {
    //something to happen on login
  }
  return $q.reject(response);
}, this));
};

this.logout = function () { 
  $http.get('/j_spring_security_logout').then(_.bind(function () {
    //something to happen on logout
  }, this));
};

如果无法更改文件名，我会自己打电话给他们。我只是想知道这是否有可能找到一种方法，但如果它过于复杂我会花费，因为其余的脚本工作：）

Answer 1

使用GNU sed：

sed -r 's/([A-Z][^A-Z.]+)/\1./g;s/[0-9]{4}/.&/g;s/([0-9])([0-9]{4})[^$]/\1.\2./;s/SXXEXXW/SXXEXX.W/;s/(S[0-9][0-9])\./\1/'

示例：

$ echo Nashville2012SXXEXXW.ac3 | sed -r 's/([A-Z][^A-Z.]+)/\1./g;s/[0-9]{4}/.&/g;s/([0-9])([0-9]{4})[^$]/\1.\2./;s/SXXEXXW/SXXEXX.W/;s/(S[0-9][0-9])\./\1/'
Nashville.2012.SXXEXX.W.ac3

$ echo HowToGetAwayWithMurderSXXEXXW.ac3 | sed -r 's/([A-Z][^A-Z.]+)/\1./g;s/[0-9]{4}/.&/g;s/([0-9])([0-9]{4})[^$]/\1.\2./;s/SXXEXXW/SXXEXX.W/;s/(S[0-9][0-9])\./\1/'
How.To.Get.Away.With.Murder.SXXEXX.W.ac3

$ echo HawaiiFive02010S03E08W.ac3 | sed -r 's/([A-Z][^A-Z.]+)/\1./g;s/[0-9]{4}/.&/g;s/([0-9])([0-9]{4})[^$]/\1.\2./;s/SXXEXXW/SXXEXX.W/;s/(S[0-9][0-9])\./\1/'
Hawaii.Five.0.2010.S03E08.W.ac3

在大写字符前插入句点

1 个答案: