我来自Qt,我有一个对话框类,并使用它来从主窗口打开对话框:
void MainWindow::on_pushButton_clicked(){
Dialog *x = new Dialog();
x->show();}
现在我想用WPF做同样的事情。 如何创建一个对话框以及如何使用它?
答案 0 :(得分:0)
定义Window
以用作输入对话框:
XAML:
<Window x:Class="WpfApplication1.MyInputDialog"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:local="clr-namespace:WpfApplication1"
mc:Ignorable="d"
Title="MyInputDialog"
Height="130"
Width="300">
<DockPanel Margin="15">
<UniformGrid DockPanel.Dock="Bottom"
Margin="5"
Rows="1"
>
<Button Content="Ok"
x:Name="bOk"
IsDefault="True"
Click="bOk_Click"
HorizontalAlignment="Center"
/>
<Button Content="Cancel"
x:Name="bCancel"
IsCancel="True"
Click="bCancel_Click"
HorizontalAlignment="Center"
/>
</UniformGrid>
<DockPanel Margin="5" >
<TextBlock DockPanel.Dock="Left"
Text="Input a value:"
/>
<TextBox x:Name="tbResult"/>
</DockPanel>
</DockPanel>
</Window>
代码隐藏:
/// <summary>
/// Interaction logic for MyInputDialog.xaml
/// </summary>
public partial class MyInputDialog : Window
{
public MyInputDialog()
{
InitializeComponent();
}
private void bOk_Click(object sender, RoutedEventArgs e)
{
DialogResult = true;
}
private void bCancel_Click(object sender, RoutedEventArgs e)
{
DialogResult = false;
}
}
然后在主Window
展示MyInputDialog
模式ShowDialog
并检查TextBox
private void Button_Click(object sender, RoutedEventArgs e)
{
var dialog = new MyInputDialog();
if(dialog.ShowDialog()== true)
{
var input = dialog.tbResult.Text;
}
}