如何计算PHP中两个日期时间之间的微小差异?
答案 0 :(得分:346)
以上答案适用于旧版本的PHP。现在使用DateTime类进行任何日期计算,因为PHP 5.3是常态。 例如
$start_date = new DateTime('2007-09-01 04:10:58');
$since_start = $start_date->diff(new DateTime('2012-09-11 10:25:00'));
echo $since_start->days.' days total<br>';
echo $since_start->y.' years<br>';
echo $since_start->m.' months<br>';
echo $since_start->d.' days<br>';
echo $since_start->h.' hours<br>';
echo $since_start->i.' minutes<br>';
echo $since_start->s.' seconds<br>';
$ since_start是DateInterval个对象。请注意,days属性是可用的(因为我们使用DateTime类的diff方法生成DateInterval对象)。
上面的代码将输出:
1837天总计5年0个月
10天
6小时
14分钟2秒
获得总分钟数:
$minutes = $since_start->days * 24 * 60;
$minutes += $since_start->h * 60;
$minutes += $since_start->i;
echo $minutes.' minutes';
这将输出:
2645654分钟
这两个日期之间经过的实际分钟数。 DateTime类将夏令时(取决于时区)考虑在内,而“旧方法”则不会。阅读有关日期和时间http://www.php.net/manual/en/book.datetime.php
的手册答案 1 :(得分:317)
以下是答案:
$to_time = strtotime("2008-12-13 10:42:00");
$from_time = strtotime("2008-12-13 10:21:00");
echo round(abs($to_time - $from_time) / 60,2). " minute";
答案 2 :(得分:80)
从过去最多的一个中减去过去最多的一个并除以60.
时间以Unix格式完成,所以它们只是一个显示January 1, 1970, 00:00:00 GMT
答案 3 :(得分:27)
<?php
$date1 = time();
sleep(2000);
$date2 = time();
$mins = ($date2 - $date1) / 60;
echo $mins;
?>
答案 4 :(得分:14)
它适用于我的程序,我正在使用<script type="text/javascript" src="..."></script>
,您可以在here上查看date_diff
手册。
date_diff
你得到你想要的结果。
答案 5 :(得分:12)
使用时区的另一种方式。
$start_date = new DateTime("2013-12-24 06:00:00",new DateTimeZone('Pacific/Nauru'));
$end_date = new DateTime("2013-12-24 06:45:00", new DateTimeZone('Pacific/Nauru'));
$interval = $start_date->diff($end_date);
$hours = $interval->format('%h');
$minutes = $interval->format('%i');
echo 'Diff. in minutes is: '.($hours * 60 + $minutes);
答案 6 :(得分:9)
我为我的博客网站写了这个函数(过去的日期和服务器的日期之间的差异)。它会给你一个这样的输出
“49秒前”,“20分钟前”,“21小时前”等等
我使用的函数可以让我了解传递日期与服务器日期之间的差异。
<?php
//Code written by purpledesign.in Jan 2014
function dateDiff($date)
{
$mydate= date("Y-m-d H:i:s");
$theDiff="";
//echo $mydate;//2014-06-06 21:35:55
$datetime1 = date_create($date);
$datetime2 = date_create($mydate);
$interval = date_diff($datetime1, $datetime2);
//echo $interval->format('%s Seconds %i Minutes %h Hours %d days %m Months %y Year Ago')."<br>";
$min=$interval->format('%i');
$sec=$interval->format('%s');
$hour=$interval->format('%h');
$mon=$interval->format('%m');
$day=$interval->format('%d');
$year=$interval->format('%y');
if($interval->format('%i%h%d%m%y')=="00000")
{
//echo $interval->format('%i%h%d%m%y')."<br>";
return $sec." Seconds";
}
else if($interval->format('%h%d%m%y')=="0000"){
return $min." Minutes";
}
else if($interval->format('%d%m%y')=="000"){
return $hour." Hours";
}
else if($interval->format('%m%y')=="00"){
return $day." Days";
}
else if($interval->format('%y')=="0"){
return $mon." Months";
}
else{
return $year." Years";
}
}
?>
将其保存为文件,假设为“date.php”。从另一个页面调用该函数
<?php
require('date.php');
$mydate='2014-11-14 21:35:55';
echo "The Difference between the server's date and $mydate is:<br> ";
echo dateDiff($mydate);
?>
当然你可以修改函数来传递两个值。
答案 7 :(得分:9)
我认为这会对你有帮助
function calculate_time_span($date){
$seconds = strtotime(date('Y-m-d H:i:s')) - strtotime($date);
$months = floor($seconds / (3600*24*30));
$day = floor($seconds / (3600*24));
$hours = floor($seconds / 3600);
$mins = floor(($seconds - ($hours*3600)) / 60);
$secs = floor($seconds % 60);
if($seconds < 60)
$time = $secs." seconds ago";
else if($seconds < 60*60 )
$time = $mins." min ago";
else if($seconds < 24*60*60)
$time = $hours." hours ago";
else if($seconds < 24*60*60)
$time = $day." day ago";
else
$time = $months." month ago";
return $time;
}
答案 8 :(得分:8)
function date_getFullTimeDifference( $start, $end )
{
$uts['start'] = strtotime( $start );
$uts['end'] = strtotime( $end );
if( $uts['start']!==-1 && $uts['end']!==-1 )
{
if( $uts['end'] >= $uts['start'] )
{
$diff = $uts['end'] - $uts['start'];
if( $years=intval((floor($diff/31104000))) )
$diff = $diff % 31104000;
if( $months=intval((floor($diff/2592000))) )
$diff = $diff % 2592000;
if( $days=intval((floor($diff/86400))) )
$diff = $diff % 86400;
if( $hours=intval((floor($diff/3600))) )
$diff = $diff % 3600;
if( $minutes=intval((floor($diff/60))) )
$diff = $diff % 60;
$diff = intval( $diff );
return( array('years'=>$years,'months'=>$months,'days'=>$days, 'hours'=>$hours, 'minutes'=>$minutes, 'seconds'=>$diff) );
}
else
{
echo "Ending date/time is earlier than the start date/time";
}
}
else
{
echo "Invalid date/time data detected";
}
}
答案 9 :(得分:6)
更通用的版本,以天,小时,分钟或秒为单位返回结果,包括分数/小数:
function DateDiffInterval($sDate1, $sDate2, $sUnit='H') {
//subtract $sDate2-$sDate1 and return the difference in $sUnit (Days,Hours,Minutes,Seconds)
$nInterval = strtotime($sDate2) - strtotime($sDate1);
if ($sUnit=='D') { // days
$nInterval = $nInterval/60/60/24;
} else if ($sUnit=='H') { // hours
$nInterval = $nInterval/60/60;
} else if ($sUnit=='M') { // minutes
$nInterval = $nInterval/60;
} else if ($sUnit=='S') { // seconds
}
return $nInterval;
} //DateDiffInterval
答案 10 :(得分:5)
这是我在php&gt;中显示“xx times ago”的方式5.2 ..这里有关于DateTime对象
的更多信息//Usage:
$pubDate = $row['rssfeed']['pubDates']; // e.g. this could be like 'Sun, 10 Nov 2013 14:26:00 GMT'
$diff = ago($pubDate); // output: 23 hrs ago
// Return the value of time different in "xx times ago" format
function ago($timestamp)
{
$today = new DateTime(date('y-m-d h:i:s')); // [2]
//$thatDay = new DateTime('Sun, 10 Nov 2013 14:26:00 GMT');
$thatDay = new DateTime($timestamp);
$dt = $today->diff($thatDay);
if ($dt->y > 0)
{
$number = $dt->y;
$unit = "year";
}
else if ($dt->m > 0)
{
$number = $dt->m;
$unit = "month";
}
else if ($dt->d > 0)
{
$number = $dt->d;
$unit = "day";
}
else if ($dt->h > 0)
{
$number = $dt->h;
$unit = "hour";
}
else if ($dt->i > 0)
{
$number = $dt->i;
$unit = "minute";
}
else if ($dt->s > 0)
{
$number = $dt->s;
$unit = "second";
}
$unit .= $number > 1 ? "s" : "";
$ret = $number." ".$unit." "."ago";
return $ret;
}
答案 11 :(得分:4)
<?php
$start = strtotime('12:01:00');
$end = strtotime('13:16:00');
$mins = ($end - $start) / 60;
echo $mins;
?>
输出:
75
答案 12 :(得分:1)
我找到两个日期之间差异的解决方案在这里。使用此功能,您可以找到诸如秒,分钟,小时,天,年和月之类的差异。
function alihan_diff_dates($date = null, $diff = "minutes") {
$start_date = new DateTime($date);
$since_start = $start_date->diff(new DateTime( date('Y-m-d H:i:s') )); // date now
print_r($since_start);
switch ($diff) {
case 'seconds':
return $since_start->s;
break;
case 'minutes':
return $since_start->i;
break;
case 'hours':
return $since_start->h;
break;
case 'days':
return $since_start->d;
break;
default:
# code...
break;
}
}
您可以开发此功能。我测试并为我工作。 DateInterval对象的输出在这里:
/*
DateInterval Object ( [y] => 0 [m] => 0 [d] => 0 [h] => 0 [i] => 5 [s] => 13 [f] => 0 [weekday] => 0 [weekday_behavior] => 0 [first_last_day_of] => 0 [invert] => 0 [days] => 0 [special_type] => 0 [special_amount] => 0 [have_weekday_relative] => 0 [have_special_relative] => 0 )
*/
功能用法:
$ date =过去的日期, $ diff =类型,例如:“分钟”,“天”,“秒”
$diff_mins = alihan_diff_dates("2019-03-24 13:24:19", "minutes");
祝你好运。
答案 13 :(得分:1)
$date1=date_create("2020-03-15");
$date2=date_create("2020-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
有关详细的格式说明符,请访问link。
答案 14 :(得分:1)
另一种计算分钟差异的简单方法。请注意,这是在 1 年范围内计算的示例。欲了解更多详情,请点击 here
$origin = new DateTime('2021-02-10 09:46:32');
$target = new DateTime('2021-02-11 09:46:32');
$interval = $origin->diff($target);
echo (($interval->format('%d')*24) + $interval->format('%h'))*60; //1440 (difference in minutes)
答案 15 :(得分:0)
这会有所帮助......
function get_time($date,$nosuffix=''){
$datetime = new DateTime($date);
$interval = date_create('now')->diff( $datetime );
if(empty($nosuffix))$suffix = ( $interval->invert ? ' ago' : '' );
else $suffix='';
//return $interval->y;
if($interval->y >=1) {$count = date(VDATE, strtotime($date)); $text = '';}
elseif($interval->m >=1) {$count = date('M d', strtotime($date)); $text = '';}
elseif($interval->d >=1) {$count = $interval->d; $text = 'day';}
elseif($interval->h >=1) {$count = $interval->h; $text = 'hour';}
elseif($interval->i >=1) {$count = $interval->i; $text = 'minute';}
elseif($interval->s ==0) {$count = 'Just Now'; $text = '';}
else {$count = $interval->s; $text = 'second';}
if(empty($text)) return '<i class="fa fa-clock-o"></i> '.$count;
return '<i class="fa fa-clock-o"></i> '.$count.(($count ==1)?(" $text"):(" ${text}s")).' '.$suffix;
}
答案 16 :(得分:0)
我找到了很多解决方案,但是我从来没有找到正确的解决方案。但是我创建了一些代码来查找分钟,请检查一下。
<?php
$time1 = "23:58";
$time2 = "01:00";
$time1 = explode(':',$time1);
$time2 = explode(':',$time2);
$hours1 = $time1[0];
$hours2 = $time2[0];
$mins1 = $time1[1];
$mins2 = $time2[1];
$hours = $hours2 - $hours1;
$mins = 0;
if($hours < 0)
{
$hours = 24 + $hours;
}
if($mins2 >= $mins1) {
$mins = $mins2 - $mins1;
}
else {
$mins = ($mins2 + 60) - $mins1;
$hours--;
}
if($mins < 9)
{
$mins = str_pad($mins, 2, '0', STR_PAD_LEFT);
}
if($hours < 9)
{
$hours =str_pad($hours, 2, '0', STR_PAD_LEFT);
}
echo $hours.':'.$mins;
?>
它以小时和分钟为单位给出输出,例如01:02分,如01:02
答案 17 :(得分:0)
减去时间并除以60。
以下是一个以分钟为单位计算2019/02/01 10:23:45
起经过的时间的示例:
$diff_time=(strtotime(date("Y/m/d H:i:s"))-strtotime(2019/02/01 10:23:45))/60;
答案 18 :(得分:0)
试试这个
$now = \Carbon\Carbon::now()->toDateString(); // get current time
$a = strtotime("2012-09-21 12:12:22");
$b = strtotime($now);
$minutes = ceil(($a - $b) / 3600); it will get ceiling value
答案 19 :(得分:0)
DateTime::diff
很酷,但对于这种需要单个单位结果的计算来说很尴尬。手动减去时间戳效果更好:
$date1 = new DateTime('2020-09-01 01:00:00');
$date2 = new DateTime('2021-09-01 14:00:00');
$diff_mins = abs($date1->getTimestamp() - $date2->getTimestamp()) / 60;