Question

现在我有一个JSON输出，我从Pearson的API获得：

Optional(<__NSCFArray 0x7f9b7601a910>(
{
    datasets =     (
        laad3,
        dictionary
    );
    headword = theoretically;
    id = cs1tNTvYvg;
    "part_of_speech" = adverb;
    senses =     (
                {
            definition = "used to say that something could happen, but it is extremely unlikely";
            examples =             (
                                {
                    text = "It\U2019s theoretically possible for everyone in the class to get 100%.";
                }
            );
        }
    );
    url = "/v2/dictionaries/entries/cs1tNTvYvg";
},
{
    datasets =     (
        laad3,
        dictionary
    );
    headword = theoretical;
    id = cs1tNTpDbZ;
    "part_of_speech" = adjective;
    senses =     (
                {
            definition = "relating to or based on ideas, especially scientific ideas, rather than practical work or experience";
            examples =             (
                                {
                    text = "theoretical research";
                }
            );
        }
    );
    url = "/v2/dictionaries/entries/cs1tNTpDbZ";
})

并假设上面的输出存储到：

let results = parsedResult!["results"]

XCode表示对下标的使用含糊不清，在谷歌搜索之后，似乎我必须继续使用结果类型。我需要将results的类型转换为例如[[String:String]]。 x=(ed1.getText().toString()); y=(ed2.getText().toString()); z=(ed3.getText().toString()); xx=x+""+y+""+z;？

旁注：有人知道为什么Xcode会抱怨在使用iOS 9.3的iPhone6上选择运行目标时使用下标，但在模拟器中运行时却没有（在带有iOS9.3的iPhone6上）？

Answer 1

我不明白这个问题的深层原因。但是自从XCode 7.3（或者更确切地说是Swift 2.2）以来，编译器现在抱怨在使用NSDictionary时模糊地使用下标。

为避免此错误，请将NSDictionary个实例投放到[String: AnyObject]和NSArray个实例，以[AnyObject]。

在将其解析为JSON文件Swift之后声明类型

1 个答案: