Question

伙计们我有2张桌子＆＃34;员工＆＃34;它有EMPID，EMPAGE，ADDRESS，SALARY，EMPNAME，department_id（外键参考表格＃34;部门＆＃34;）和＆＃34;部门＆＃34;有department_id，name的表...我做了一个HQL查询来选择部门

public List<Department> listDepartment() {
    List<Department> deps = sessionFactory.getCurrentSession()
                           .createCriteria(Department.class).list();
    return deps;
}

并循环遍历表以构造要由ajax请求调用的JSON对象

    public void listDepartment(HttpServletResponse response) throws IOException, JSONException {
        PrintWriter out = response.getWriter();
        JSONObject obj1 = new JSONObject();
        JSONObject obj = new JSONObject();

        for(int index = 0; index<listDepartment().size(); index++){
            obj1.put("Department ID "+index,listDepartment().get(index).getDepId());
            obj1.put("Department Name "+index,listDepartment().get(index).getDepName());

            JSONArray array = new JSONArray();
            for(Employee l : listDepartment().get(index).getEmployees()){
                array.add(l.getEmpId()+" "+l.getEmpAge()+" "+l.getSalary()+" "+l.getEmpAddress());
                obj1.put("Employees "+index, array);
            }

        }

        System.out.println(obj1);
        obj.put("MyListDep", obj1);
        response.setContentType("application/json");
        response.setCharacterEncoding("UTF-8");
        out.write(obj.toString());
        out.close();

但我找到了＆＃39; obj1＆＃39;就像这样

{＆＃34;部门名称0＆＃34;：＆＃34;名称1＆＃34;，＆＃34;部门名称1＆＃34;：＆＃34;名称2＆＃34;，＆＃34;部门名称2＆＃34;：＆＃34;名称3＆＃34;，＆＃34;部门名称3＆＃34;：＆＃34;名称4＆＃34;，＆＃34;部门名称 4＆＃34;：＆＃34; name5＆＃34;，＆＃34;员工0＆＃34;：[＆＃34; 1 10薪水1地址1＆＃34;，＆＃34; 2 20薪水2 地址2＆＃34;]，＆＃34;部门ID 0＆＃34;：1，＆＃34;部门ID 1＆＃34;：2，＆＃34;员工2＆＃34;：[＆＃34; 5 50 salary5 address5＆＃34;，＆＃34; 6 60 salary6 address6＆＃34;]，＆＃34;员工1＆＃34;：[＆＃34; 3 30 salary3 address3＆＃34;，＆＃34; 4 40 salary4 address4＆＃34;]，＆＃34; Department ID 2＆＃34;：3，＆＃34;部门ID 3＆＃34;：4，＆＃34;部门ID 4＆＃34;：5，＆＃34;员工4＆＃34;：[＆＃34; 9 90 salary9 address9＆＃34;，＆＃34; 10 100 salary10 address10＆＃34;]，＆＃34;员工3＆＃34;：[＆＃34; 7 70 salary7 address7＆＃34;，＆＃34; 8 80 salary8 address8＆＃34;]}

不保留订单..所以我希望它打印索引0的所有信息，然后索引1然后......等任何帮助??

使用hibernate和spring MVC从DB中选择时保留顺序

0 个答案: