Question

我不认为有一种方法可以让这个命令忽略引号内的逗号（在'三'之间）？

$ echo 'one,two,"three,three",four' | { IFS=',' read -a array; echo ${#array[@]}; }
5

的Nb。 echo ${#array[@]}报告数组长度..

Answer 1

在gnu-awk中使用FPAT，你可以这样做：

str='one,two,"three,three",four'

awk -v FPAT='"[^"]*"|[^,]*' '{
   print "# of columns: " NF; for(i=1; i<=NF; i++) print "Field #", i, ":", $i
}' <<< "$str"

<强>输出：

# of columns: 4
Field # 1 : one
Field # 2 : two
Field # 3 : "three,three"
Field # 4 : four

Answer 2

转义逗号：

echo 'one,two,"three\,three",four'

结果：

$ echo 'one,two,"three\,three",four' | { IFS=',' read -a array; echo ${#array[@]} ${array[2]}; }
4 "three,three"

在bash中分隔字符串，忽略引号中的分隔符

2 个答案: