Question

我想知道怎么做才能让我的程序创建一个文件，如果它还没有找到它？

public void load() throws Exception {
    try
      {
        File log = new File(FILE_NAME); //opens the file
        FileInputStream fileIn = new FileInputStream(log);
        ObjectInputStream in = new ObjectInputStream(fileIn); //de-serializes
        videosList = (ArrayList)in.readObject(); // de-serializes
        in.close(); //closes the file
        fileIn.close();
      } catch(Exception i)
      {
         i.printStackTrace();
        }

这是我得到的错误：

java.io.FileNotFoundException: Users/hanaezz/Desktop/output.ser (No such file or directory)
    at java.io.FileInputStream.open0(Native Method)
    at java.io.FileInputStream.open(FileInputStream.java:195)
    at java.io.FileInputStream.<init>(FileInputStream.java:138)
    at videostore.BinaryFile.load(BinaryFile.java:31)
    at videostore.VideoStore.<init>(VideoStore.java:33)
    at videostore.VideoStore$6.run(VideoStore.java:430)
    at java.awt.event.InvocationEvent.dispatch(InvocationEvent.java:311)
    at java.awt.EventQueue.dispatchEventImpl(EventQueue.java:756)
    at java.awt.EventQueue.access$500(EventQueue.java:97)
    at java.awt.EventQueue$3.run(EventQueue.java:709)
    at java.awt.EventQueue$3.run(EventQueue.java:703)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.security.ProtectionDomain$JavaSecurityAccessImpl.doIntersectionPrivilege(ProtectionDomain.java:76)
    at java.awt.EventQueue.dispatchEvent(EventQueue.java:726)
    at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:201)
    at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:116)
    at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:105)
    at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:101)
    at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:93)
    at java.awt.EventDispatchThread.run(EventDispatchThread.java:82)

所有额外的东西都是因为我的程序也是一个GUI程序。然后我还有一个方法可以将我的对象写入文件...

public void writeToFile() throws Exception{
        FileOutputStream outputStream = new FileOutputStream(FILE_NAME);
        ObjectOutputStream oos = new ObjectOutputStream(outputStream);
        oos.writeObject(videosList);
        oos.close();
        outputStream.close();
        }

这引发了同样的异常。我怎么能避免这个？我不知道如果他们找不到它，我不知道如何修改FIS / OIS来创建文件..或者我认为FOS / OOS更有效率呢？

Answer 1

Users/...

您错过了文件名中的前导/。因此，您无法创建它，因此您无法阅读它。

如何避免FileNotFoundException？

1 个答案: