应用基于多维数组的LINQ过滤器

时间:2016-04-09 08:08:39

标签: c# .net entity-framework linq linq-to-entities

给定实体框架查询,例如

var query = (from property in _dbContext.Properties
        join location in _db.Locations
            on property.Id equals location.PropertyId
select new PropertyDetail
{
    Url = property.Url,
    Type = property.Type,
    Title = property.Title,
    Continent = location.Continent,
    Country = location.Country,
    State = location.State,
});

我已应用过滤器,例如:

if (!string.IsNullOrWhitespace(searchFilters.Type))
{
    query = query.Where(model => model.Type == searchFilters.Type);
}
if (!string.IsNullOrWhitespace(searchFilters.Title))
{
    query = query.Where(model => model.Title.Contains(searchFilters.Title));
}

给出以下多维数组

var locations = new[]
{
    new[] {"Africa", "Algeria", ""},
    new[] {"Asia", "Hong Kong", ""},
    new[] {"Asia", "Singapore", ""},
    new[] {"Oceania", "Australia", "New South Wales"},
    new[] {"North America", "United States", "California"}
};

"如何查询"进一步限制为仅包括与指定位置{大陆,国家,州(可选)}匹配的条目?

2 个答案:

答案 0 :(得分:0)

这要求在SQL中使用所谓的相关子查询。假设它们总是占据相同的位置,您可以使用数组索引器来访问locations锯齿状数组中的元素。

query = query.Where(model => 
    locations.Any(location =>
        location[0] == model.Continent &&
        location[1] == model.Country &&
        (string.IsNullOrEmpty(location[2]) || location[2] == model.State)));

更新:由于LINQ to Entities不支持数组索引器,因此您可以将锯齿状数组转换为匿名类型的集合。 (从长远来看,最好创建一个用于实例化过滤器的类。这比记住每个索引所代表的元素更直观。)

var locationsTyped = 
    locations.Select(location => new
    {
        Continent = location[0],
        Country = location[1],
        State = location[2],
    }).ToArray();

query = query.Where(model => 
    locationsTyped.Any(location =>
        location.Continent == model.Continent &&
        location.Country == model.Country &&
        (string.IsNullOrEmpty(location.State) || location.State == model.State)));

答案 1 :(得分:0)

不幸的是,LINQ to Entities目前不支持对内存集合的连接,也不支持Contains非原始内存集合。我看到的唯一方法(实际上这里描述了另一个Entity Framework LINQ Get all items part of another collection,但现在我认为这更合适)是使用一些表达式构建帮助器来构造OR过滤器。

例如,使用Establish a link between two lists in linq to entities where clause中的PredicateUtils类,可能是这样的:

首先,添加一个小帮手方法

static Expression<Func<PropertyDetail, bool>> LocationFilter(string value, int index)
{
    if (!string.IsNullOrEmpty(value))
    {
        if (index == 0) return d => d.Continent == value;
        if (index == 1) return d => d.Country == value;
        if (index == 2) return d => d.State == value;
    }
    return null;
}

然后使用

var locationsFilter = locations.Select(location => location.Select(LocationFilter)
    .Aggregate(PredicateUtils.And)).Aggregate(PredicateUtils.Or);
if (locationsFilter != null)
    query = query.Where(locationsFilter);

为了完整性,这里是使用的助手类:

public static class PredicateUtils
{
    sealed class Predicate<T>
    {
        public static readonly Expression<Func<T, bool>> True = item => true;
        public static readonly Expression<Func<T, bool>> False = item => false;
    }
    public static Expression<Func<T, bool>> Null<T>() { return null; }
    public static Expression<Func<T, bool>> True<T>() { return Predicate<T>.True; }
    public static Expression<Func<T, bool>> False<T>() { return Predicate<T>.False; }
    public static Expression<Func<T, bool>> And<T>(this Expression<Func<T, bool>> left, Expression<Func<T, bool>> right)
    {
        if (Equals(left, right)) return left;
        if (left == null || Equals(left, True<T>())) return right;
        if (right == null || Equals(right, True<T>())) return left;
        if (Equals(left, False<T>()) || Equals(right, False<T>())) return False<T>();
        var body = Expression.AndAlso(left.Body, right.Body.Replace(right.Parameters[0], left.Parameters[0]));
        return Expression.Lambda<Func<T, bool>>(body, left.Parameters);
    }
    public static Expression<Func<T, bool>> Or<T>(this Expression<Func<T, bool>> left, Expression<Func<T, bool>> right)
    {
        if (Equals(left, right)) return left;
        if (left == null || Equals(left, False<T>())) return right;
        if (right == null || Equals(right, False<T>())) return left;
        if (Equals(left, True<T>()) || Equals(right, True<T>())) return True<T>();
        var body = Expression.OrElse(left.Body, right.Body.Replace(right.Parameters[0], left.Parameters[0]));
        return Expression.Lambda<Func<T, bool>>(body, left.Parameters);
    }

    static Expression Replace(this Expression expression, Expression source, Expression target)
    {
        return new ExpressionReplacer { Source = source, Target = target }.Visit(expression);
    }

    class ExpressionReplacer : ExpressionVisitor
    {
        public Expression Source;
        public Expression Target;
        public override Expression Visit(Expression node)
        {
            return node == Source ? Target : base.Visit(node);
        }
    }
}

更新:根据评论中的要求,以下是locations List<Location>的解决方案:

var locationsFilter = locations.Select(location =>
{
    var filter = PredicateUtils.Null<PropertyDetail>();
    if (!string.IsNullOrEmpty(location.Continent))
        filter = filter.And(d => d.Continent == location.Continent);
    if (!string.IsNullOrEmpty(location.Country))
        filter = filter.And(d => d.Country == location.Country);
    if (!string.IsNullOrEmpty(location.State))
        filter = filter.And(d => d.State == location.State);
    return filter;
}).Aggregate(PredicateUtils.Or);