Question

我正在编写一个查询以获取mysql中的好友列表。查询正确获取结果。

这是我正在使用的查询：

SELECT (
        SELECT COUNT( * )               
        FROM
            cpo_conversation_reply               
        WHERE
            user_id_fk = u.id 
            AND user_id_rec = $user_id              
            AND read_unread_status =0  
            AND c.property_id = p_id
    ) AS unread_msg,
    u.id AS user_id, c.c_id, u.first_name, u.last_name, u.user_name,
    u.online_status AS loginstatus, c.user_one, c.user_two, u.user_img,
    c.property_id, p.locality, p.city, c.online_status          
FROM
    cpo_conversation c,
    property_register u,
    property_for_sale p          
WHERE
    CASE 
        WHEN c.user_one = '$user_id' THEN c.user_two = u.id                     
        WHEN c.user_two = '$user_id' THEN c.user_one = u.id                 
    END            
    AND (
        c.user_one = '$user_id' 
        OR c.user_two = '$user_id'               
    )                                     
    AND p.id = c.property_id           
ORDER BY
   c.c_id DESC

现在我想要隐藏已删除的聊天的朋友..

为此我在条件中添加以下条件：

c.hide_chat_1 != '1' OR c.hide_chat_2 != '1'

之后，这个查询是这样的：

SELECT (
        SELECT COUNT( * )                  
        FROM
            cpo_conversation_reply                  
        WHERE
            user_id_fk = u.id 
            AND user_id_rec = $user_id                  
            AND read_unread_status =0  
            AND c.property_id = p_id                  
    ) AS unread_msg,
    u.id AS user_id, c.c_id, u.first_name, u.last_name, u.user_name,
    u.online_status AS loginstatus, c.user_one, c.user_two, u.user_img,
    c.property_id, p.locality, p.city, c.online_status                  
FROM
    cpo_conversation c,
    property_register u,
    property_for_sale p                  
WHERE
    CASE 
        WHEN c.user_one = '$user_id' THEN c.user_two = u.id                  
        WHEN c.user_two = '$user_id' THEN c.user_one = u.id                  
    END 
    AND (
        c.user_one = '$user_id'                  
        OR c.user_two = '$user_id'                  
    )                   
    AND (
        c.hide_chat_1 != '1'                  
        OR c.hide_chat_2 != '1'                  
    )                  
    AND p.id = c.property_id                  
ORDER BY
    c.c_id DESC

但隐藏聊天状态的朋友不是隐藏1。

有人可以帮我这个吗？

Answer 1

请改用：

c.hide_chat_1 <> '1'
OR c.hide_chat_2 <> '1'

mysql多个“AND”条件无法正常工作

1 个答案: