Java简单客户端服务器程序

时间:2016-04-09 06:49:06

标签: java client-server

我编写了一个简单的java代码,用于从服务器向客户端发送消息,客户端应分别显示它。 代码是。

Client.java

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.net.Socket;
   public class Client {

    public static void main(String[] args) throws Exception {
        Socket client_socket = new Socket("localhost", 1235);
        BufferedReader reader = new BufferedReader(new InputStreamReader(client_socket.getInputStream()));
        BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(client_socket.getOutputStream()));
        String serverMsg = null;
        while ((serverMsg = reader.readLine()) != null) {
            System.out.println("Client: " + serverMsg);

        }
    }
}

Server.java

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.net.ServerSocket;
import java.net.Socket;
import java.util.Scanner;

public class Server {

    public static void main(String[] args) throws Exception {
        ServerSocket server_socket;
        server_socket = new ServerSocket(1235);
        while (true) {
            Socket mysocket = server_socket.accept();

            BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(mysocket.getOutputStream()));
            BufferedReader reader = new BufferedReader(new InputStreamReader(mysocket.getInputStream()));
            writer.write("Hello omkar ");

            System.out.println("data sent");
        }
    }

}

问题: 现在的问题是,当我运行这些代码时,我得到服务器端发送的消息数据,但客户端控制台是空白的。请帮我找出错误。

2 个答案:

答案 0 :(得分:3)

在服务器代码中而不是使用BufferedWriter,请使用PrintWriter。

while (true) {
        Socket mysocket = server_socket.accept();

        PrintWriter out = new PrintWriter(socket.getOutputStream(), true);            
        BufferedReader reader = new BufferedReader(new InputStreamReader(mysocket.getInputStream()));
        out.println("Hello World!");

        System.out.println("data sent");
    }

这适用于我的系统。试试这个。

答案 1 :(得分:2)

你正在读行,但你不是在写行。在邮件中添加行终止符,或使用newline()

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