我有一段代码,我试图按降序对TreeMap
中的键进行排序,因为当我只使用TreeMap
时,它会根据键进行排序,这些键是按升序排列的订购。我收到的错误是:
找不到适合TreeMap的构造函数。
这里有什么问题?
import java.util.TreeMap;
import java.util.Map;
import java.util.Comparator;
import java.util.Map.Entry;
import java.util.SortedMap;
public class ChangeMachine {
public TreeMap<Double, Integer> dispenseChange(Double changeAmount, TreeMap<Double, Integer> coinsMap) {
TreeMap<Double, Integer> coinDispenserMap = new TreeMap<>();
for (Map.Entry<Double, Integer> coin : coinsMap.entrySet()) {
if (!(changeAmount > coin.getKey())) {
coinDispenserMap.put(coin.getKey(), 0);
continue;
}
int noOfCoins = (int) (changeAmount / coin.getKey());
coinDispenserMap.put(coin.getKey(), noOfCoins);
Double remainder = changeAmount % coin.getKey();
changeAmount = remainder;
if (changeAmount == 0.0) {
break;
}
}
return coinDispenserMap;
}
public static void main(String[] args) {
ChangeMachine ref = new ChangeMachine();
TreeMap<Double, Integer> coinsMap = new TreeMap<Double, Integer>(new Comparator<Entry<Double, Integer>>() {
public int compare(Entry<Double, Integer> coin1, Entry<Double, Integer> coin2) {
return (coin2.getKey().compareTo(coin1.getKey()));
}
});
coinsMap.put(0.25, 10);
coinsMap.put(0.01, 10);
coinsMap.put(0.05, 10);
coinsMap.put(0.10, 10);
TreeMap<Double, Integer> coinDispenserMap = ref.dispenseChange(0.86, coinsMap);
for (Map.Entry<Double, Integer> coin : coinDispenserMap.entrySet()) {
System.out.println(coin.getKey() + " : " + coin.getValue());
}
}
}
答案 0 :(得分:4)
试试这个:
Comparator<Double> comparator = Double::compare;
Comparator<Double> reverseComparator = comparator.reversed();
Map<Double,Integer> reversedMap = new TreeMap(reverseComparator);
答案 1 :(得分:2)
比较器的类型是Entry<Double, Integer>
,它需要是地图密钥类型的超类型,即Double
。由于Entry<Double, Integer>
不是Double
的超类型,constructor can't be matched。
相反,请尝试:
Map<Double, Integer> coinsMap =
new TreeMap<Double, Integer>(new Comparator<Double>() {
public int compare(Double coin1, Double coin2) {
return (coin2.compareTo(coin1));
}
});
另外,对于一些样式,您可能需要考虑将coinsMap
声明为Map<Double, Integer> coinsMap = new TreeMap<>()
,就像我在上面的代码段中所做的那样。查看Josh Bloch的精彩书籍Effective Java 2nd Ed.(第4章与此相关),以获得有关Java的精彩建议。