Question

JSON文件：

{
    "stock": [
            {
                "symbol": "AVGO",
                "name": "Broadcom Ltd.",
                "sector": "Technology",
                "industry": "Semiconductors",
                "SCTR": "97.8",
                "delta": "2.5",
                "close": "154.97",
                "vol": "2297509"
            }, 
            {
                "symbol": "CBS",
                "name": "CBS Corp.",
                "sector": "Cyclicals",
                "industry": "Entertainment",
                "SCTR": "92.3",        
                "delta": "-3.6",
                "close": "53.58",
                "vol": "4045416"
            }
       ]
}

PHP：

$jsona = json_decode($json, true);
echo $jsona['stock']['symbol'];

为什么我无法获得符号？我怎样才能获得所有符号值？谢谢！

Answer 1

在您的情况下，$stocks['stock']是您要循环的数组。我更改了变量名称以了解循环：

$stocks = json_decode($json, true);
foreach($stocks['stock'] AS $stock){
    echo $stock['symbol'] ."<br>";
}

返回

AVGO

CBS

Answer 2

你必须使用$jsona['stock'][0]['symbol']因为stock包含一个数组，所以你必须指定你正在访问的数组的哪个元素。然后，您可以使用foreach循环遍历$jsona['stock']数组的每个元素。

Answer 3

＆＃34; stock＆＃34;的价值是一个数组。所以你可以这样做：

echo $jsona['stock'][0]['symbol'];
echo $jsona['stock'][1]['symbol'];

或循环播放：

foreach ($jsona['stock'] as $stock) {
    echo "Symbol: {$stock['symbol']}\n";
    echo "Name: {$stock['name']}\n";
    echo "Sector: {$stock['sector']}\n\n";
}

产生：

Symbol: AVGO
Name: Broadcom Ltd.
Sector: Technology

Symbol: CBS
Name: CBS Corp.
Sector: Cyclicals

无法在PHP中从JSON返回值

3 个答案: