Question

我将以下纯文本存储为磁盘中的txt文件

No.     Time           Source                Destination           Protocol Length Info
     93 3.505189000    192.168.1.125         204.79.197.200        HTTP     1160   GET /fd/ls/l?IG=C0F1A7E0A49E484DA6CAC4FA64BE2415&Type=Event.CPT&DATA={%22pp%22:{%22S%22:%22L%22,%22FC%22:12,%22BC%22:416,%22H%22:459,%22BP%22:647,%22CT%22:655,%22IL%22:8},%22ad%22:[-1,-1,1349,640,1349,1759,1]}&P=SERP&DA=Co3b HTTP/1.1

Frame 93: 1160 bytes on wire (9280 bits), 1160 bytes captured (9280 bits) on interface 0
Ethernet II, Src: HonHaiPr_8c:81:48 (e0:06:e6:8c:81:48), Dst: Nintendo_ce:a4:2d (00:22:aa:ce:a4:2d)
Internet Protocol Version 4, Src: 192.168.1.125 (192.168.1.125), Dst: 204.79.197.200 (204.79.197.200)
    Host: cn.bing.com\r\n
    Accept: image/webp,*/*;q=0.8
    User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/42.0.2311.154 Safari/537.36 LBBROWSER\r\n
    Referer: http://cn.bing.com/search?q=wireshark%E5%88%86%E6%9E%90%E8%A7%86%E9%A2%91&go=%E6%8F%90%E4%BA%A4&qs=n&form=QBRE&pq=wireshark%E5%88%86%E6%9E%90%E8%A7%86%E9%A2%91&sc=2-13&sp=-1&sk=&cvid=6AAF0CC941DB44F2AFA26B89D6E6ABF6\r\n

当我使用BuffeRedreader来处理这个文件时，我想摆脱'\ r \ n'并将没有'\ r \ n'的新txt写入新文件。

像这样的代码

BufferedReader br = new BufferedReader(new FileReader("D:/wiresharkpack/a.txt"));
        String line = "";
        BufferedWriter bw = new BufferedWriter(new FileWriter("D:/wiresharkpack/rlt/a.txt"));
        while ((line=br.readLine())!=null){
            System.out.println(line.replaceAll("\r\n", " "));
            bw.write(line+"\\r\\n");
            bw.newLine();
        }

但结果是'\ r \ n'仍然在这里。

我试图在String中处理这个问题。像这样

  String lines = "http://b2.bst.126.net/newpage/r/c/c.css?v=1458632076134\r\n123"; 

     System.out.println(lines);
     //String[] arr = Pattern.compile("[\r\n]+|[\n\r]+|[\n]+").split(lines.trim());
     String[] arr = lines.split("\r\n");

     System.out.println();
     for (int i = 0; i < arr.length; i++) {
             System.out.println(arr[i]);
     }

结果是'\ r \ n'不再出现在结果中。

使用变量字符串，'\ r \ n'可以转义，而在文件中则不能转义。如此困惑

Answer 1

您的评论代码：

// Use try-with-resources
BufferedReader br = new BufferedReader(new FileReader("D:/wiresharkpack/a.txt"));

 // No need to initialize. It's wasteful and misleading.
String line = "";

// Use try-with-resources
BufferedWriter bw = new BufferedWriter(new FileWriter("D:/wiresharkpack/rlt/a.txt"));

while ((line=br.readLine())!=null){

    // readLine() has already removed the \r\n, no need for the replaceAll()
    System.out.println(line.replaceAll("\r\n", " "));

    // You are specifically adding \r\n, so why are you confused to see them in the output?
    bw.write(line+"\\r\\n");

    // You are specifically writing a newline, so why are you confused to see double in the output?
    bw.newLine();
}

您的代码应为：

try (BufferedReader br = new BufferedReader(new FileReader("D:/wiresharkpack/a.txt"));
     BufferedWriter bw = new BufferedWriter(new FileWriter("D:/wiresharkpack/rlt/a.txt"))) {
   String line;
   while ((line = br.readLine()) != null) {
      System.out.println(line);
      bw.write(line);
      bw.newLine(); // Remove to get rid of all \r\n in output
   }
}

Answer 2

line.replaceAll()创建一个新字符串，因此不会更改line。你必须这样做

line = line.replaceAll();

更改行。

Answer 3

您可能希望从第一个解决方案中删除此行。

bw.write(line+"\\r\\n");

这应该是你第一个解决方案的诀窍。

另外，删除此...

bw.newLine();

来自文档：

换行 public void newLine（）抛出IOException 写一个行分隔符。行分隔符字符串由系统属性line.separator定义，不一定是单个换行符（＆＃39; \ n＆＃39;）字符。抛出： IOException - 如果发生I / O错误

https://docs.oracle.com/javase/7/docs/api/java/io/BufferedWriter.html#newLine()

Answer 4

在我看来，您正在尝试删除输入中四个字符的字符串\r\n，而不是\r\n这两个字符。

e.g。

String s = "Host: cn.bing.com\r\n";
String s2 = s2.replaceAll("\\\\r\\\\n", "");
System.out.println(s2);

打印

Host: cn.bing.com

简而言之，您有一个\（反斜杠），然后r然后\然后n而不是\r（返回）和{{1 （新行）字符。

为什么这个Java代码使用与String split \ r \ n不同的BuffedReader

4 个答案: