Question

我有一个控制器它需要多个模型函数结果并将其传递给控制器我就像这样做了

adpreview_ctrl.php
        public function showBusinessReviews($vehicleid){


            $data=array();
            $data['details']=$this->ads_model->getBusinessReviews($vehicleid);
            $data['noOfReviews']=$this->ads_model->countReviews($vehicleid);
            $this->load->view('pages/templates/header');
            $this->load->view('pages/viewReviews',$data);
            $this->load->view('pages/templates/footer');
        }
    public function countBusinessReviews($vehicleid){
        $data['details']=$this->ads_model->countReviews($vehicleid);
        $this->load->view('pages/templates/header');
            $this->load->view('pages/viewReviews',$data);
            $this->load->view('pages/templates/footer');
        }
    }

viewReviews.php

    <?php 

    foreach($noOfReviews as $reviewAmount){
    echo $reviewAmount.'Reviews';

    }

    foreach($details as $review){
        $Breview=$review->rating;


    if($details==null)
    {?>



    <?php echo '<center><b><h3>No any reviews has been posted yet!</h3></b></center>';?>
            <a href="<?php echo base_url().'adpreview_ctrl/getad_preview'.'/'.$review->Vehicleid; ?>"><input type="submit" name="ok" class="btn btn-primary btn-lg" value="ok"></a>


         <?php }
        else{
            ?>

    Ads_model.php

    public function getBusinessReviews($Vehicleid){
            $status="Approved";
            $this->db->select("*");
            $query=$this->db->where('Vehicleid',$Vehicleid);
            $query=$this->db->where('Status',$status);  
            $query=$this->db->get('businessreviews');
            return $query->result();        
        }


    public function countReviews($Vehicleid){
        $status="Approved";
        $this->db->select("*");
            $query=$this->db->where('Vehicleid',$Vehicleid);
            $query=$this->db->where('Status',$status);  
            $query=$this->db->get('businessreviews');
        return $query->num_rows(); 
    }

我需要知道的是，它错误地说它无法识别$noOfReviews。

  foreach($noOfReviews as $reviewAmount){
        echo $reviewAmount.'Reviews';

        }

我需要知道如何在视图中检索多个模型函数数据，并且$noOfReviews仅给出用户给出的评论。所以他们在没有使用foreach循环的情况下如何获得它的值，这里不需要使用foreach循环。

Answer 1

试试这个：
模型：

public function countReviews($Vehicleid) {
    $status = "Approved";
    $this->db->select("*");
    $query = $this->db->where('Vehicleid', $Vehicleid);
    $query = $this->db->where('Status', $status);
    // it will return with only the number of data
    return $query->count_all_results('businessreviews');
}

viewReviews.php

<?php
    // show number of reviews
    echo $noOfReviews . 'Reviews';

    // show details if exists
    if(!empty($details)) {
        foreach($details as $review) {
            // echo what you want
        }
    } else { 
        echo 'No details.';
    }
?>

当多个模型函数从控制器

1 个答案: