Question

我正在寻找一个选项如何从路线中删除{one？} / {two？} / {three？} / {four？} / {five？}这个。这会自动添加到每个路线中像

public static void main(String[] args) throws Exception {
    //Parse the args
    if (args.length != 1) {
        System.err.println("Main()/: String to MD5 digest should be first parameter\n");
        System.out.println("Main()/: Require now a clear password with 4 char :");
        sc = new Scanner(System.in);
        in = sc.nextLine();
        force = 2;
    }
    else{
        in = args[0];
        force = Integer.parseInt(args[1]);
    }
    //Set the count of Breakers
    count=force;
    //Make the hash
    Hashmaker hm = new Hashmaker(in,"Hashmaker");
    hm.start();
    System.out.println("Main()/: Managing the breakers will start !");

    //Get the hash
    hash=hm.getHash();
    //Manage the Breakers
    f = new File(count);
    for(int i=0; i<count;i++){
        Hashbreaker hb = new Hashbreaker(hash,"HashBreaker"+i);
        f.enfiler(hb);
        hb.start();
    }
}

在使用以下路线的路线档案中

v1/webapi/login/{one?}/{two?}/{three?}/{four?}/{five?}
v1/webapi/logout/{one?}/{two?}/{three?}/{four?}/{five?}

任何人都可以遇到同样的问题吗？

Answer 1

简短回答是 - 您无法将其删除。此方法https://github.com/laravel/framework/blob/5.2/src/Illuminate/Routing/ControllerInspector.php#L132添加那些通配符参数。

摆脱它的唯一方法是重写Router并使用你自己的ControllerInspector，但这是毫无意义的，很难实现。

<强>更新

但如果你真的想这样做，那就有一个hacky解决方案：

    foreach (\Route::getRoutes() as $route) {
        $route->setUri(preg_replace('%\{one\?\}/\{two\?\}/\{three\?\}/\{four\?\}/\{five\?\}$%', '',
            $route->getUri()));
    }

将此代码放入RouteServiceProvider.php boot方法。

在Laravel 5路线中摆脱{one？} / {two？} / {three？} / {four？} / {five？}字符串

1 个答案: