我正在用C#编程,我现在有以下的2D数组:
int[,] results = {
{ 4, 7, 9, 3, 8, 6, 4},
{ 4, 8, 6, 4, 8, 5, 6},
{ 7, 3, 9, 2, 2, 1, 8}
};
我想创建一个循环或函数,输出3个独立的数组,复制每行的值。
e.g。输出:
row1 = {4, 7, 9, 3, 8, 6, 4}
row2 = {4, 8, 6, 4, 8, 5, 6}
等
我已经能够将每行的值复制到一个单独的字符串中,然后使用以下代码行在控制台中写入:
for (int a = 1; a < (rows+1); a++)
{
for (int b = 1; b < (columns+1); b++)
{
scores = scores + " " + results[(a-1), (b-1)];
}
scores = "";
}
答案 0 :(得分:3)
您需要从2D数组转换为锯齿状数组
int[,] array = { { 4, 7, 9, 3, 8, 6, 4},
{ 4, 8, 6, 4, 8, 5, 6},
{ 7, 3, 9, 2, 2, 1, 8}
};
int[][] jagged = new int[array.GetLength(0)][];
for (int i = 0; i < array.GetLength(0); i++)
{
int[] row = new int[array.GetLength(1)];
for (int j = 0; j < array.GetLength(1); j++)
{
row[j] = array[i, j];
}
jagged[i] = row;
}
int[] row1 = jagged[0];
int[] row2 = jagged[1];
int[] row3 = jagged[2];
多维数组和锯齿状数组之间的区别:
//multidimensional array
int[,] multi = { { 7, 2, 6, 1 }, { 3, 5, 4, 8 } };
//array of arrays (jagged array)
int[][] jagged = new int[][] { new int[] { 7, 2, 6, 1 }, new int[] { 3, 5, 4, 8 } };
答案 1 :(得分:1)
LINQ变种:
var m0 = new int[,] { { 1, 2 }, { 3, 4 } };
var rows = Enumerable.Range(0, m0.GetLength(0)).Select(i => Enumerable.Range(0, m0.GetLength(1)).Select(j => m0[i, j]));
foreach (var r in rows) Console.WriteLine(string.Join(" ", r));
Console.ReadLine();
'更聪明'的变体(flattern a array,取n个值):
var rows = m0.Cast<int>().Select((v, i) => new { i = i / m0.GetLength(1), v }).GroupBy(e => e.i).Select(g => g.Select(e => e.v));
答案 2 :(得分:0)
使用JsonSoft作为
的小菜一碟var json = JsonConvert.SerializeObject(results);
int[][] arr = JsonConvert.DeserializeObject<int[][]>(json);
int[] arr1 = arr[0];
int[] arr2 = arr[1];
int[] arr3 = arr[2];