如何将多维(2D)数组按行分成多个1D数组?

时间:2016-04-08 06:44:36

标签: c# arrays rows

我正在用C#编程,我现在有以下的2D数组:

int[,] results = {                                  
{ 4, 7, 9, 3, 8, 6, 4},                                  
{ 4, 8, 6, 4, 8, 5, 6},                                  
{ 7, 3, 9, 2, 2, 1, 8}    
};

我想创建一个循环或函数,输出3个独立的数组,复制每行的值。

e.g。输出:

row1 = {4, 7, 9, 3, 8, 6, 4}    
row2 = {4, 8, 6, 4, 8, 5, 6}

我已经能够将每行的值复制到一个单独的字符串中,然后使用以下代码行在控制台中写入:

for (int a = 1; a < (rows+1); a++)                
{                    
    for (int b = 1; b < (columns+1); b++)                    
    {                        
        scores = scores + " " + results[(a-1), (b-1)];                    
    }                    
    scores = "";                
}

3 个答案:

答案 0 :(得分:3)

您需要从2D数组转换为锯齿状数组

int[,] array = {  { 4, 7, 9, 3, 8, 6, 4},
                    { 4, 8, 6, 4, 8, 5, 6},
                    { 7, 3, 9, 2, 2, 1, 8}
                };            

int[][] jagged = new int[array.GetLength(0)][];
for (int i = 0; i < array.GetLength(0); i++)
{
    int[] row = new int[array.GetLength(1)];
    for (int j = 0; j < array.GetLength(1); j++)
    {
        row[j] = array[i, j];
    }
    jagged[i] = row;
}

int[] row1 = jagged[0];
int[] row2 = jagged[1];
int[] row3 = jagged[2];

多维数组和锯齿状数组之间的区别:

//multidimensional array
int[,] multi = { { 7, 2, 6, 1 }, { 3, 5, 4, 8 } };
//array of arrays (jagged array) 
int[][] jagged = new int[][] { new int[] { 7, 2, 6, 1 }, new int[] { 3, 5, 4, 8 } };

答案 1 :(得分:1)

LINQ变种:

var m0 = new int[,] { { 1, 2 }, { 3, 4 } };
var rows = Enumerable.Range(0, m0.GetLength(0)).Select(i => Enumerable.Range(0, m0.GetLength(1)).Select(j => m0[i, j]));
foreach (var r in rows) Console.WriteLine(string.Join(" ", r));
Console.ReadLine();

'更聪明'的变体(flattern a array,取n个值):

var rows = m0.Cast<int>().Select((v, i) => new { i = i / m0.GetLength(1), v }).GroupBy(e => e.i).Select(g => g.Select(e => e.v));

答案 2 :(得分:0)

使用JsonSoft作为

的小菜一碟
var json = JsonConvert.SerializeObject(results);
int[][] arr = JsonConvert.DeserializeObject<int[][]>(json);

int[] arr1 = arr[0];
int[] arr2 = arr[1];
int[] arr3 = arr[2];