Question

这里我试图从特定网站中提取黑名单IP列表，并尝试制作以下字段的Excel表格： IP，日期......新的更新代码是：

import xlwt
import urllib

def Bl():
    link = 'https://www.dshield.org/ipsascii.html?limit=100'
    p = urllib.urlopen(link)
    text = p.readlines()


    wbk = xlwt.Workbook()
    sheet = wbk.add_sheet('python')
    sheet.write(0,0,'Blacklist IP')
    sheet.write(0,1,'Reports')
    sheet.write(0,2,'abcd')
    sheet.write(0,3,'date')
    sheet.write(0,4,'Date')

    row = 1 #counter for rows.
    col = 0 #counter for columns.
    x = 0   #counter for printing the n'th element in the string w.

    for line in text:
        li = line.strip()
        w = line.split()


        if not li.startswith("#"):
            sheet.write(row,col,w[0])
            sheet.write(row,1,w[1])
            sheet.write(row,2,w[2])
            sheet.write(row,3,w[3])
            sheet.write(row,4,w[4])
            row = row + 1

    wbk.save('new.xls')

Bl()

Answer 1

我相信它应该是这样，虽然我的python并不是很棒：

import xlwt
import urllib

link = 'https://www.dshield.org/ipsascii.html?limit=100'
p = urllib.urlopen(link)
text = p.readlines()


wbk = xlwt.Workbook()
sheet = wbk.add_sheet('Blacklist IP')

row = 1 #counter for rows.
col = 0 #counter for columns.
#x = 0   #counter for printing the n'th element in the string w.

for line in text:
    li = line.strip()
    w = line.split()
    print "The line " + line + " was split into " + len(w) + " size"

    for i in range(0,len(w)-1):
        if not li.startswith("#") and not li.isspace():
            sheet.write(row,col,w[i])
            #x = x + 1      
            col = col + 1
            if col > 256:
                print "Line of " + li
                print "Row: " + row
                print "Col: " + col
                raise ValueError('Too many columns, can\'t insert ' + w)

    row = row + 1

wbk.save('new.xls')

推理是我相信你每次写一个值时都应该更改列，因为这似乎是导致你当前的错误。我也相信你应该在每一行之后改变行，而不仅仅是在代码的末尾，这看起来是多余的

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请在以下程序中指出我的错误

1 个答案: