Question

Dim connection As New adodb.connection        
Dim sql As String
Dim years As Integer
years = 2011

所以我在这里得到了一些很好的声明变量。现在，我将展示完美无缺的陈述：

sql = "insert into crimeData(reportYear) values(2011)"
connection.Execute sql

注意我在这一年里硬编码。现在，如果我尝试：

sql = "insert into crimeData(reportYear) values(years)"
connection.Execute sql

将变量名称替换为值，我收到错误：No value given for one or more required parameters

不可否认，我认为这是一个简单的语法问题，或者是一些缺少变量的元数据。请赐教。我怎样才能在这里正确地交换变量（所以我可以以编程方式使用它，而不是在值中进行硬编码）

Answer 1

如果您对连接SQL的要求更高，则可以从此功能中受益：

' Converts a value of any type to its string representation.
' The function can be concatenated into an SQL expression as is
' without any delimiters or leading/trailing white-space.
'
' Examples:
'   SQL = "Select * From TableTest Where [Amount]>" & CSql(12.5) & "And [DueDate]<" & CSql(Date) & ""
'   SQL -> Select * From TableTest Where [Amount]> 12.5 And [DueDate]< #2016/01/30 00:00:00#
'
'   SQL = "Insert Into TableTest ( [Street] ) Values (" & CSql(" ") & ")"
'   SQL -> Insert Into TableTest ( [Street] ) Values ( Null )
'
' Trims text variables for leading/trailing Space and secures single quotes.
' Replaces zero length strings with Null.
' Formats date/time variables as safe string expressions.
' Uses Str to format decimal values to string expressions.
' Returns Null for values that cannot be expressed with a string expression.
'
' 2016-01-30. Gustav Brock, Cactus Data ApS, CPH.
'
Public Function CSql( _
    ByVal Value As Variant) _
    As String

    Const vbLongLong    As Integer = 20
    Const SqlNull       As String = " Null"

    Dim Sql             As String
    Dim LongLong        As Integer

    #If Win32 Then
        LongLong = vbLongLong
    #End If
    #If Win64 Then
        LongLong = VBA.vbLongLong
    #End If

    Select Case VarType(Value)
        Case vbEmpty            '    0  Empty (uninitialized).
            Sql = SqlNull
        Case vbNull             '    1  Null (no valid data).
            Sql = SqlNull
        Case vbInteger          '    2  Integer.
            Sql = Str(Value)
        Case vbLong             '    3  Long integer.
            Sql = Str(Value)
        Case vbSingle           '    4  Single-precision floating-point number.
            Sql = Str(Value)
        Case vbDouble           '    5  Double-precision floating-point number.
            Sql = Str(Value)
        Case vbCurrency         '    6  Currency.
            Sql = Str(Value)
        Case vbDate             '    7  Date.
            Sql = Format(Value, " \#yyyy\/mm\/dd hh\:nn\:ss\#")
        Case vbString           '    8  String.
            Sql = Replace(Trim(Value), "'", "''")
            If Sql = "" Then
                Sql = SqlNull
            Else
                Sql = " '" & Sql & "'"
            End If
        Case vbObject           '    9  Object.
            Sql = SqlNull
        Case vbError            '   10  Error.
            Sql = SqlNull
        Case vbBoolean          '   11  Boolean.
            Sql = Str(Abs(Value))
        Case vbVariant          '   12  Variant (used only with arrays of variants).
            Sql = SqlNull
        Case vbDataObject       '   13  A data access object.
            Sql = SqlNull
        Case vbDecimal          '   14  Decimal.
            Sql = Str(Value)
        Case vbByte             '   17  Byte.
            Sql = Str(Value)
        Case LongLong           '   20  LongLong integer (Valid on 64-bit platforms only).
            Sql = Str(Value)
        Case vbUserDefinedType  '   36  Variants that contain user-defined types.
            Sql = SqlNull
        Case vbArray            ' 8192  Array.
            Sql = SqlNull
        Case Else               '       Should not happen.
            Sql = SqlNull
    End Select

    CSql = Sql & " "

End Function

尝试将变量用作值vba到sql

1 个答案: