Question

我是新编码我想知道我的错误是什么。要求转换为double的图表添加到数组然后对数组中除frist和last之外的所有项目求和。来自文本文件

这是文本文件：

8.7 6.5 0.1 3.2 5.7 9.9 8.3 6.5 6.5 1.5 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0

import java.io.*;
import java.util.*;
import java.text.*;
public class BaseClass
{
   public static void main(String args[]) throws IOException
   {
      NumberFormat fmt = NumberFormat.getNumberInstance();
      fmt.setMinimumFractionDigits(4);
      fmt.setMaximumFractionDigits(4);
      Scanner sf = new Scanner(new File("C:\\temp_Name\\DataGym.in.txt"));
      int maxIndx = -1;
      String text[] = new String[1000];

      while(sf.hasNext()) {
      maxIndx++;
      text[maxIndx] = sf.nextLine();
   }
   sf.close();
   int contestant = 0;

   for (int j = 0; j <= maxIndx; j++) {
     Scanner sc = new Scanner(text[j]);
     double sum = 0;
     double answer=0;
     double array[] = new double[1000];
     while(sc.hasNext()){
       Arrays.sort(array);
       double b=sc.nextDouble();  
     } 
     contestant++;
     answer = answer + sum;
     System.out.println("For Competitor #" + contestant + ", the average is " + (answer/8) );
   }
  }
}

我想打印像：

For Competitor #1, the average is 5.8625
For Competitor #2, the average is 0.0000
For Competitor #3, the average is 1.0000

Answer 1

在上面列出的代码中，您永远不会更改变量sum＆amp;的值。回答，所以它们将始终为0，如初始化语句中那样。

Answer 2

根据我对您的问题的理解，您希望丢弃竞争对手的最佳和最差结果，然后计算剩余数字的平均值。目前，您没有将每个竞争对手的值写入您排序的阵列中。你快到了。

你会发现使用ArrayList和ArrayList比使用字符串和双精度数组更容易。

例如，要读入文件中的行：

File file = new File( "C:\\temp_Name\\DataGym.in.txt" );

ArrayList<String> lines = new ArrayList<String>();

// Use try() like this to automatically close the file when finished
try( Scanner scanner = new Scanner( file ) ) {
   while( scanner.hasNext() )
      lines.add( scanner.nextLine() );
}
catch( Exception ex ) {
   // TODO: handle a failure to read your input file gracefully...
}

然后处理每个竞争对手的结果：

for( String line : lines ) {
   Scanner scanner = new Scanner(line);
   ArrayList<Double> values = new ArrayList<Double>();
   while( scanner.hasNextDouble() )
      values.add( scanner.nextDouble() );

   Collections.sort(values);
   double sum = 0;

   // Sum starting from the second element, and finishing before the last
   for( int index = 1; index < values.size() - 1; ++index )
      sum += values.get(index);

   // TODO: What do you want to do if there are two or fewer values?
   double mean = sum / values.size() - 2;

   // Do whatever you want to log this contestants results...
}

除了第一个和最后一个，我如何总结数组中的所有项目

2 个答案: