我正在接收使用SJCL加密的数据到我需要解密的iOS应用程序中。另一端使用SJCL和AES CCM模式,Apple的 CommonCrypto 不支持这种模式,因此我使用VPCCMCrypt库。发送SJCL密文时,无法对另一方进行任何更改。
以下是我的解密方法:
+ (NSData *)decryptSjcl:(NSDictionary *)cipher password:(NSString *)password {
if (cipher == nil || password == nil) {
return nil;
}
int version = [cipher[@"v"] intValue];
NSString *iv = cipher[@"iv"];
uint iter = [cipher[@"iter"] unsignedIntValue];
uint ks = [cipher[@"ks"] unsignedIntValue];
uint ts = [cipher[@"ts"] unsignedIntValue];
NSString *mode = cipher[@"mode"];
NSString *adata = cipher[@"adata"];
NSString *algorithm = cipher[@"cipher"];
NSString *salt = cipher[@"salt"];
NSString *ct = cipher[@"ct"];
if (version != 1 || ! [@"aes" isEqualToString:algorithm]) {
return nil;
}
NSData *rawIv = [[NSData alloc] initWithBase64EncodedString:iv options:0];
NSData *rawSalt = [[NSData alloc] initWithBase64EncodedString:salt options:0];
NSData *rawAdata = [[NSData alloc] initWithBase64EncodedString:adata options:0];
NSData *cipherData = [[NSData alloc] initWithBase64EncodedString:ct options:0];
NSData *key;
NSMutableData *decipheredData = nil;
if ([@"ccm" isEqualToString:mode]) {
key = [Cryptor sjclAesKeyForPassword:password salt:rawSalt iterations:iter keySize:ks];
decipheredData = [Cryptor decryptAesCcmData:cipherData iv:rawIv key:key adata:rawAdata tagSize:ts];
}
return decipheredData;
}
SJCL密钥生成:
+ (NSData *)sjclAesKeyForPassword:(NSString *)password salt:(NSData *)salt iterations:(uint)iterations keySize:(uint)keySizeBits {
NSMutableData *derivedKey = [NSMutableData dataWithLength:keySizeBits / 8];
int result = CCKeyDerivationPBKDF(kCCPBKDF2,
password.UTF8String,
[password lengthOfBytesUsingEncoding:NSUTF8StringEncoding],
salt.bytes,
salt.length,
kCCPRFHmacAlgSHA256,
iterations,
derivedKey.mutableBytes,
derivedKey.length);
NSAssert(result == kCCSuccess, @"Unable to create AES key for password: %d", result);
return derivedKey;
}
AES CCM解密:
+ (NSMutableData *)decryptAesCcmData:(NSData *)cipherData iv:(NSData *)iv key:(NSData *)key adata:(NSData *)adata tagSize:(uint)tagSizeBits {
VPCCMCrypt *ccm = [[VPCCMCrypt alloc] initWithKey:key
iv:iv
adata:adata
tagLength:tagSizeBits / 8];
[ccm decryptDataWithData:cipherData
finishedBlock:^(NSData *data) {
NSString *result = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(@"Decrypted SJCL message: %@", result);
}
errorBlock:^(NSError *error) {
NSLog(@"ERROR");
}];
return nil;
}
正确解析来自SJCL的所有输入数据(IV,盐,密钥大小,标签大小,PBKDF迭代,密文),并从NSData
编码表示解码为Base64
。密码使用相同。包括创建的AES密钥在内的所有数据都不是零。
最后,它在验证CCM标签的VPCCMCrypt
内失败(标签不同)。上面的代码有什么问题吗?是否有其他iOS / Objective-C / Swift库可以解密AES CCM甚至更好的SJCL?我对SJCL库的JavaScript包装器不感兴趣。
为了进行测试,我使用SJCL's demo page中的简单加密数据。
修改
如评论中所述,SJCL为CCM模式发送16字节IV而不是最多12字节,然后在解密时将其内部钳位到最多12个字节。这是更新的解密方法:
+ (NSData *)decryptSjcl:(NSDictionary *)cipher password:(NSString *)password {
if (cipher == nil || password == nil) {
return nil;
}
int version = [cipher[@"v"] intValue];
NSString *iv = cipher[@"iv"];
uint iter = [cipher[@"iter"] unsignedIntValue];
uint ks = [cipher[@"ks"] unsignedIntValue];
uint ts = [cipher[@"ts"] unsignedIntValue];
NSString *mode = cipher[@"mode"];
NSString *adata = cipher[@"adata"];
NSString *algorithm = cipher[@"cipher"];
NSString *salt = cipher[@"salt"];
NSString *ct = cipher[@"ct"];
if (version != 1 || ! [@"aes" isEqualToString:algorithm]) {
return nil;
}
NSMutableData *rawIv = [[NSMutableData alloc] initWithBase64EncodedString:iv options:0];
NSMutableData *rawSalt = [[NSMutableData alloc] initWithBase64EncodedString:salt options:0];
NSMutableData *rawAdata = [[NSMutableData alloc] initWithBase64EncodedString:adata options:0];
NSMutableData *cipherData = [[NSMutableData alloc] initWithBase64EncodedString:ct options:0];
NSData *key;
NSData *decipheredData = nil;
if ([@"ccm" isEqualToString:mode]) {
key = [Cryptor sjclAesKeyForPassword:password salt:rawSalt iterations:iter keySize:ks];
// Clamp the SJCL IV - They use a 16 byte IV for CCM mode which is against specification and they do a funky
// clamping. CCM mode IV should be max 13 bytes long. They almost always clamp it to 13 bytes but save the whole
// 16 bytes in their JSON container.
// for (L=2; L<4 && ol >>> 8*L; L++) {}
// if (L < 15 - ivl) { L = 15-ivl; }
// iv = w.clamp(iv,8*(15-L));
int64_t ivl = rawIv.length;
int64_t ol = cipherData.length - (ts / 8);
int64_t L = 2;
for (L = 2; L < 4 && ol >> 8*L; L++) {}
if (L < 15 - ivl) {
L = 15 - ivl;
}
NSRange subrange = NSMakeRange(0, (NSUInteger)(15 - L));
decipheredData = [Cryptor decryptAesCcmData:cipherData iv:[rawIv subdataWithRange:subrange] key:key adata:rawAdata tagSize:ts];
}
else {
decipheredData = nil;
}
return decipheredData;
}
最后一件事是验证TAG,我无法做到。有什么想法吗?
答案 0 :(得分:0)
SJCL在AES-CCM模式下不使用整个(128/192 / 256bit)IV,但是演示页面显示了它。尝试用更少的字节。
在这里您可以找到IV长度计算的工作原理: http://bitwiseshiftleft.github.io/sjcl/doc/symbols/src/core_ccm.js.html
for (L=2; L<4 && ol >>> 8*L; L++) {}
if (L < 15 - ivl) { L = 15-ivl; }
iv = w.clamp(iv,8*(15-L));