import java.util.Scanner;
public class Recursion
{
//variables to hold string values
public static String s1 = new String(new char[10]);
public static String s2 = new String(new char[10]);
public static String s3 = new String(new char[11]);
public static String charSet = new String(new char[11]);
//variables to hold number values
public static int numberOne;
public static int numberTwo;
public static int numberThree;
public static int maxCharCount;
public static int[] numberSet = new int[10];
//function which generates a number
public static void checkForEquality()
{
numberOne = numberTwo = numberThree = 0;
int i;
int j;
for (i = 0; i < s1.length(); i++)
{
for (j = 0; j < maxCharCount; j++)
{
if (s1.charAt(i) == charSet.charAt(j))
{
if (i == 0 && numberSet[j] == 0)
return;
//generate the number
numberOne = (numberOne * 10) + numberSet[j];
}
}
}
for (i = 0; i < s2.length(); i++)
{
for (j = 0; j < maxCharCount; j++)
{
if (s2.charAt(i) == charSet.charAt(j))
{
if (i == 0 && numberSet[j] == 0)
return;
//generate number
numberTwo = (numberTwo * 10) + numberSet[j];
}
}
}
for (i = 0; i < s3.length(); i++)
{
for (j = 0; j < maxCharCount; j++)
{
if (s3.charAt(i) == charSet.charAt(j))
{
if (i == 0 && numberSet[j] == 0)
return;
//generate the number
numberThree = (numberThree * 10) + numberSet[j];
}
}
}
}
public static void display(){
if (numberOne + numberTwo == numberThree) {
//display the output
int i=0;
System.out.println();
System.out.print(" Summation Puzzle solved. ");
System.out.print("n");
System.out.print(s1);
System.out.print("<==>");
System.out.print(numberOne);
System.out.print("n");
System.out.print(s2);
System.out.print("<==>");
System.out.print(numberTwo);
System.out.print("n");
System.out.print(s3);
System.out.print("<==>");
System.out.print(numberThree);
System.out.print("n");
//loop to show the result
for (i = 0; i < maxCharCount; i++)
{
System.out.println(charSet.charAt(i));
System.out.print("<==>");
System.out.print(numberSet[i]);
System.out.print("n");
}
System.exit(0);
}
}
//recursive function which will call itself
public static void Combinations(int indexCounter, int[] availableSet)
{
int i;
if (indexCounter != 0)
{
for (i = 0; i < 10; i++)
{
numberSet[indexCounter] = i;
if (availableSet[i] == 1)
{
availableSet[i] = 0;
Combinations(indexCounter + 1, availableSet);
availableSet[i] = 1;
}
}
}
if (indexCounter == maxCharCount)
checkForEquality();
}
public static void createCharSet()
{
int i;
int setIndex;
int present;
int j;
setIndex = 0;
for (i = 0; i < s1.length(); i++)
{
present = 0;
for (j = 0; j < setIndex; j++)
{
if (s1.charAt(i) == charSet.charAt(j))
{
present = 1;
}
}
if (present == 0)
{
charSet = StringFunctions.changeCharacter(charSet, setIndex++, s1.charAt(i));
}
}
for (i = 0; i < s2.length(); i++)
{
present = 0;
for (j = 0; j < setIndex; j++)
{
if (s2.charAt(i) == charSet.charAt(j))
{
present = 1;
}
}
if (present == 0)
{
charSet = StringFunctions.changeCharacter(charSet, setIndex++, s2.charAt(i));
}
}
for (i = 0; i < s3.length(); i++)
{
present = 0;
for (j = 0; j < setIndex; j++)
{
if (s3.charAt(i) == charSet.charAt(j))
{
present = 1;
}
}
if (present == 0)
{
charSet = StringFunctions.changeCharacter(charSet, setIndex++, s3.charAt(i));
}
}
maxCharCount = setIndex;
}
public static void calculateSummation()
{
int loop;
if (maxCharCount > 10)
{
System.out.print("Please check the input again");
return;
}
else
{
int[] avaliableSet = new int[10];
for (loop = 0; loop < 10; loop++)
{
avaliableSet[loop] = 1;
}
Combinations(0, avaliableSet);
}
}
//main method
public static void main(String[]args) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter the first String :");
s1 = scan.next();
System.out.print("Enter the second String :");
s2 = scan.next();
System.out.print("Enter the thirsd String :");
s3 = scan.next();
createCharSet();
System.out.print(" result of your 3 three strings = ");
System.out.print(charSet);
calculateSummation();
checkForEquality();
display();
}
}
每次运行程序时，它只为每个值赋值0。我希望能够为每个非数字字符分配1-10的值。 有人能帮助我吗？
看起来应该是这样的 Sample output
答案 0 :(得分：0)
首先，如果正确格式化代码，您可能会发现调试更容易。我记得你昨晚发布的帖子，你遇到了类似的语法问题。如果您将代码格式化为这样，您可能会发现代码更容易阅读：
//function which generates a number
public static void checkForEquality(){
numberOne = numberTwo = numberThree = 0;
int i;
int j;
for (i = 0; i < s1.length(); i++){
for (j = 0; j < maxCharCount; j++){
if (s1.charAt(i) == charSet.charAt(j)){
if (i == 0 && numberSet[j] == 0)
return;
//generate the number
numberOne = (numberOne * 10) + numberSet[j];
}
}
}
for (i = 0; i < s2.length(); i++){
for (j = 0; j < maxCharCount; j++){
if (s2.charAt(i) == charSet.charAt(j)){
if (i == 0 && numberSet[j] == 0)
return;
//generate number
numberTwo = (numberTwo * 10) + numberSet[j];
}
}
}
查看代码的这一部分，看看它是否仍然正确地遵循您的算法。您可能会发现错误，您可以使用格式正确的代码找到自己的错误。如果你看看你的previous question（我已经回答），你会找到一个有用的链接，指导你编写更好的代码。
另外，我没有尝试在我自己的IDE中编译它，但你应该看看Eclipse。您可以自动定位许多小错误。