通过在SQL服务器上使用CTE获取用户的所有管理员

时间:2016-04-07 14:26:58

标签: sql sql-server common-table-expression recursive-query

我试图吸引用户的所有高层管理人员。

例如。 丹王(专家) - > Adam Lion(产品经理) - > Reina Ken(IT主管) - > Michael Lorren(董事) - > Pat Deep(首席执行官)

我想在下面的一栏中向丹金的高层管理人员展示:

Adam
Reina
Michael
Pat

注意: Get all employees under manager with CTE 我使用了这个链接,我决定接受经理的用户。

我尝试根据示例代码转换代码,但它不起作用:

;WITH OS_MANAGERS AS 
(
SELECT USERID, MANAGERUSERID 
from OSMANAGERS
), Manager AS
(
SELECT USERID, MANAGERUSERID
from OS_MANAGERS
where [userID]='mbalasubrama'
union all
SELECT B.USERID, B.MANAGERUSERID
from Manager A
inner join OS_MANAGERS B ON A.MANAGERUSERID= B.USERID
)
select A.USERID , a.MANAGERUSERID
from OS_MANAGERS A
left join Manager B on A.USERID=B.USERID
where A.[userID]='mbalasubrama'

只有我看到用户的经理,其他顶级的经理不会来

结果:

2 个答案:

答案 0 :(得分:2)

你的代码看起来有点太复杂了......试试这个:

DECLARE @tbl TABLE(USERID INT,MANAGERUSERID INT,Name VARCHAR(100));
INSERT INTO @tbl VALUES
 (1,NULL,'CEO Pat')
,(2,1,'Director Michael')
,(3,2,'HIT Reina')
,(4,3,'PM Adam')
,(5,4,'Dan King');

WITH ManagerRecursive AS
(
    SELECT USERID, MANAGERUSERID,Name
    from @tbl
    where [userID]=5
    union all
    SELECT tbl.USERID, tbl.MANAGERUSERID,tbl.Name
    from ManagerRecursive AS MR
    INNER JOIN @tbl AS tbl ON tbl.USERID=MR.MANAGERUSERID
)
SELECT * FROM ManagerRecursive ;

结果

USERID  MANAGERUSERID   Name
5       4               Dan King
4       3               PM Adam
3       2               HIT Reina
2       1               Director Michael
1       NULL            CEO Pat

答案 1 :(得分:0)

你可以看到我的代码:

WITH ManagerRecursive AS
(
   SELECT  [USERID],[MANAGERUSERID]

  FROM [EBA].[dbo].[OSMANAGERS]

   where [userID]='dking'

    union all

    SELECT tbl.USERID, tbl.MANAGERUSERID

    from ManagerRecursive AS MR

    INNER JOIN [EBA].[dbo].[OSMANAGERS] AS tbl ON tbl.USERID=MR.MANAGERUSERID

)
SELECT * FROM ManagerRecursive ; 

结果:

Userid manageruserid

dking   tkir
tkir    skara