Question

我写下面的代码有点复杂。是否可以对在较少步骤内减少代码而不是级联进行任何修改。

$countries='IN,US,AU,MY,TH,KR,TW';      //list country codes separated by comma
$countries=explode(',',$countries);     //partition from ,
$countries=implode('\',\'',$countries);     //add ' at start and end of the country code
$countries="'".$countries."'";              //add ' to first and last country code
$countries=explode(',',$countries);         //create array by breaking it from ,
print_r($countries);

输出

数组（[0] =＆gt;'IN'[1] =＆gt;'美国'[2] =＆gt;'AU'[3] =＆gt;'MY'[4] =＆gt;'TH' [5] =＆GT; 'KR'[6] =＆gt; 'TW'）

Answer 1

对于如下输出：

数组（[0] =＆gt;'IN'[1] =＆gt;'美国'[2] =＆gt;'AU'[3] =＆gt;'MY'[4] =＆gt;'TH' [5] =＆gt;'KR'[6] =＆gt;'TW'）

你可以这样做：

$countries='IN,US,AU,MY,TH,KR,TW';      //list country codes separated by comma
$countries= explode(',',$countries);     //partition from ,
$countries= "'".implode("','",$countries)."'";    

$countries=explode(',',$countries);         //create array by breaking it from ,
print_r($countries);

Answer 2

你可以这样做

$countries='IN,US,AU,MY,TH,KR,TW';     
$countries=explode(',',$countries);    
$countries2 = array_map(function($val) { return "'".$val."'";} , $countries);
print_r($countries2);

<强>输出

数组（[0] =＆gt;＆＃39; IN＆＃39; [1] =＆gt;＆＃39;美国＆＃39; [2] =＆gt;＆＃39; AU＆＃39; [3] =＆gt;＆＃39;我＆＃39; [4] =＆gt;＆＃39; TH＆＃39; [5] =＆gt;＆＃39; KR＆＃39; [6] =＆gt;＆＃39; TW＆＃39;）

Answer 3

<?php
 $countries='IN,US,AU,MY,TH,KR,TW';
 $countries = preg_replace("/(\b)/", "'$1", $countries);
 $countries = explode(",", $countries);
 Var_dump($countries);
 ?>

链接到工作示例：请记住更改为preg_replace http://www.phpliveregex.com/p/ff7

Answer 4

您可以使用正则表达式：

$countries = 'IN,US,AU,MY,TH,KR,TW';
$countries = preg_replace('/([A-z]{2})/', "'$1'", $countries);
$countries = explode(',',$countries);

Answer 5

正则表达式替换中的

$1, $2... $n是对括在括号中的匹配的引用。 $0将是整个匹配，$1将是第一个带括号的捕获，$2将是第二个，等等。

$1 is a reference to whatever is matched by the first (.*)
$2 is a reference to (\?|&)
$4 is a reference to the second (.*)

$countries = 'IN,US,AU,MY,TH,KR,TW';
$countries = explode(',',preg_replace('/([A-Z]{2})/', "'$1'", $countries));
print_r($countries);

<强>输出

数组（[0] =＆gt;＆＃39; IN＆＃39; [1] =＆gt;＆＃39;美国＆＃39; [2] =＆gt;＆＃39; AU＆＃39; [3] =＆gt;＆＃39;我＆＃39; [4] =＆gt;＆＃39; TH＆＃39; [5] =＆gt; ＆＃39; KR＆＃39; [6] =＆gt; ＆＃39; TW＆＃39; ）

参考：http://uk.php.net/manual/en/function.preg-replace.php

如何减少这个字符串操作代码

5 个答案: