Question

我只是c ++的初学者所以我只是想制作一个简单的程序。但是我犯了很多麻烦。请告诉我如何解决这个错误，因为我对构造函数一无所知。

#include <iostream>
#include<windows.h>
#include<fstream>
using namespace std;

int main()
{
MessageBox(NULL,"YOU HAVE BEEN PROMOTED TO TEST THIS CONSOLE APP FOR FREE!!","PROMOTION!!",NULL);
cout << "Hello world!............ first do you want this program to changeyour files  to save progress??" << endl;
int save;
cout << "press 1 to allow press 2 to deny!!"<<endl;
cin >> save;
if(save == 1){

ofstream myfile;
myfile.open ("data.txt");
}
if(save == 2 );


cout<<"set up done!!!"<<endl;


return 0;
}

这是我的Boss课程

#ifndef BOSS_H
#define BOSS_H


class Boss
{

    int boss_helth(){
        int boss_helth0 = 200;
        return boss_helth();

    }
 void Punch(){



 }


};

最后我的球员类

#ifndef PLAYER_H
#define PLAYER_H


class Player
{

 int Player_helth(){
 Player_helth0 = 200;
 return player_helth0;

 }
 void patt(){
public:

    int power_punch = - 20;

 }





};

#endif // PLAYER_H

我不知道为什么会收到此错误。

Answer 1

看起来错误是当你试图声明变量Player_helth0时，你没有指出一个类型。它应该是：

int Player_helth0 = 200;

我也看到了另一个（无关的）问题。在Boss_helth中，您的返回值应该是变量Boss_helth0，但是您将返回对该函数的调用。

我收到了这个错误：隐式声明

1 个答案: