Question

我点击按钮多次打开弹出窗口时遇到问题。我会清楚地解释我的问题。

嗨，这是我的父视图客户表单。如果我输入客户名称地址类型，街道，位置，地点，然后选择区域附近有一个添加按钮area.Suppose如果区域不在列表中意味着我必须添加。所以我点击该添加按钮，它将打开 AreaPartial 视图作为弹出窗口。

输入详细信息并单击“创建”按钮后，它将数据保存在db中，当它关闭时显示相同的弹出窗口，这意味着当我单击x标记[在弹出窗口的右上角时）。现在一切正常。

现在我的问题是我打开弹出窗口，单击按钮并添加区域并关闭弹出窗口，然后在父视图中单击主保存按钮，我必须添加另一个区域，所以我单击添加按钮再次但它不会打开弹出窗口。这是我的问题。

我的控制器代码，用于保存在局部视图弹出窗口中输入的数据

  public ActionResult AreaPartialView()
  {
    ViewBag.CityID = new SelectList(db.Cities, "CityID", "DisplayName");
    return View("AreaPartialView");
  }
   [HttpPost]

  public ActionResult AddAreaInfo(CustomerViewModel objareaVM)
   {
     var objAreaID = Guid.NewGuid();
     ViewBag.CityID = new SelectList(db.Cities, "CityID", "DisplayName", objareaVM.CityID);

     var ObjArea = new Area()
    {
    AreaID =objAreaID,
    DisplayName = objareaVM.Area,
    PrintName = objareaVM.Area,
    CityID = objareaVM.CityID,
    IsActive = true,
    IsDeleted = false,
    CreatedDate = DateTime.Now,
    EditedDate = DateTime.Now,
    LastActiveOn = DateTime.Now,
    RowID = Guid.NewGuid(),
    CreatedSessionID = Guid.NewGuid(),
    EditedSessionID = Guid.NewGuid(),
    OfflineMode = false,
    OfflineID = Guid.NewGuid()
    };

    db.Areas.Add(ObjArea);
    db.SaveChanges();
    ModelState.Clear();

  return Json(objAreaID);
   }

我的j-query代码，在父视图中单击添加按钮后，将区域局部视图显示为弹出窗口

  <script src="~/Scripts/jquery-1.10.2-ui.js"></script>
  <link rel="stylesheet"href="http://code.jquery.com/ui/1.10.2/themes/smoothness/jquery-ui.css" />

  <script type="text/javascript">
   $("#AddArea").click(function () {
   $('#AddAreaNew').dialog("open");
   });
   $(function () {
   $('#AddAreaNew').dialog({
   autoOpen: false,
   width: 400,
   height: 500,
   resizable: false,
   title: 'Add Area',
   modal: true,
   open: function (event, ui) {
       $(this).load("@Url.Action("AreaPartialView", "Customer")");
   },
   buttons: {
       "Close": function () {
           $(this).dialog("close");
       }
    }
    });
    });

我的部分查看代码

   @Html.Label("Area" , new { @class = "control-label" })
   @Html.TextBoxFor(model => model.Area, new { @class = "form-control", type = "text" ,id ="AreaName"})
   @Html.ValidationMessageFor(model => model.Area)

   @Html.Label("City")        
   @Html.DropDownList("CityID", null, "Select", new { @class = "form-control " })

 <script src="~/Scripts/jquery-1.10.4-ui.min.js"></script>
 <link href="~/Content/jquery-ui-1.10.4.custom.min.css" rel="stylesheet" />
 <script src="~/Scripts/jquery-ui-1.8.24.min.js"></script>
 <script type="text/javascript">

  function SaveArea() {
  debugger;
  var Area = $("#AreaName").val();
  var CityID = $("#CityID").val();
  alert(Area);
  var AreaAdd = { "Area": '' +Area + '', "CityID": CityID };
   $.post("/Customer/AddAreaInfo", AreaAdd, function(data) { 
    var option = new Option(Area, data);
        $('#AreaID').append($(option));
        alert("sucess");
        window.close();
  });
  }

这是我的问题，我无法多次打开我的弹出窗口。我尽力解释我的问题。请任何人帮我解决这个问题。

提前谢谢..

Answer 1

作为一个简单的例子，也许这样的事情会对你有所帮助。

<style>
.floatingbox
{
z-index:99999;
position:absolute;
/* and more of your styling here, the main point is to make to appear above any other element on the page */
}
</style>

<div class="floatingbox" id="inputbox">

</div>

编辑：<input type="button" value="Add Field" onclick="WhenIGetClicked(this)"/>

function WhenIGetClicked(e)
{
RefershContent();
document.getElementbyId('input').style.left = e.style.left;
document.getElementbyId('input').style.top = e.style.top; // show div at position of button but you can change it to where-ever
}

function RefreshContent()
{
 // put your html in here for the different fields you'll need in the div 
document.getElementbyId('inputbox').innerHTML = '';
// add the rest of your html mark up but make it as a function so it can be 'refreshed' and look like a new blank form each time, i found this easier than making a partial view and having to deal with loading it into the div/messing with javascript inside the partial view but may be personal preference :)
}

function OnSaveClick()
{
var SomeValueYouWantToPass = document.getElementbyId('inputboxinsidethediv').value; // or innerHTML works sometimes too if it's not getting the value correctly

$.ajax({
type:post,
url: '/MyController/ActionName',
dataType: 'json',
data: { MyVariableOnTheControllerSide: SomeValueYouWantToPass },
success: function()
{
alert('hey it worked!'); // or refresh the page to load the new field, etc
}
)}

}
</script>

现在在控制器端：

public JsonResult UpdateField(string MyVariableOnTheControllerSide)
{
//do something with the data. 
return Json('Hey it worked!', JsonRequestBehavior.AllowGet);
}

如果您想将它作为一个类传递，因为这是您在控制器上设置的方式，那么在获取值时，您必须在HTML标记一侧创建类作为Json对象（你甚至可以在div中执行for循环控制并动态获取值而不是伸出到每个元素以获得它的值）。我经常做弹出窗口的方式非常基本。如果您需要澄清或者我错过了您的观点，请告诉我:)）

在MVC4中多次单击按钮打开弹出窗口的问题？

1 个答案: