Question

我正在尝试使用apache camel swagger组件创建休息服务。

现在我有这个骆驼语境：

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:camel="http://camel.apache.org/schema/spring"
       xsi:schemaLocation="
         http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
         http://camel.apache.org/schema/spring http://camel.apache.org/schema/spring/camel-spring.xsd">

  <!-- a bean for user services -->
  <bean id="personService" class="www.tempuri.person.PersonService"/>


  <camelContext id="myCamel" xmlns="http://camel.apache.org/schema/spring">

    <restConfiguration component="servlet" bindingMode="auto" contextPath="myService/rest" port="8080">
      <dataFormatProperty key="prettyPrint" value="true"/>
    </restConfiguration>

    <!-- defines the rest services using the context-path /Equipment -->
    <rest path="/getPerson/persons" consumes="application/json,application/xml" produces="application/json,application/xml">
      <description>Person rest service</description>
       <post uri="/search" type="www.tempuri.person.model.GetPerson" 
                outType="www.tempuri.person.model.GetPerson">
        <description>Get Person(s)</description>
        <param name="body" type="body" description="Get Person(s)" required="true"/>            
        <responseMessage code="400" message="Bad Request" />
        <responseMessage code="200" message="Person Data" />
        <responseMessage code="401" message="Unauthorized" />
        <to uri="bean:personService?method=getPersons"/>
      </post>
    </rest>
  </camelContext>
</beans>

以下是我的模特类GetPerson：

package www.tempuri.person.model;

import javax.xml.bind.annotation.XmlRootElement;
import com.fasterxml.jackson.annotation.JsonRootName;

import io.swagger.annotations.ApiModel;
import io.swagger.annotations.ApiModelProperty;

@ApiModel(description = "Represents Persons")
@XmlRootElement(name="getPerson")
@JsonRootName(value = "getPerson")
public class GetPerson {

    @ApiModelProperty(value = "Application Area of GetPerson", required = true)
    private ApplicationArea applicationArea;

    @ApiModelProperty(value = "Data Area of GetPerson", required = true)
    private DataArea dataArea;

    /**
     * @return the dataArea
     */
    public DataArea getDataArea() {
        return dataArea;
    }

    /**
     * @param dataArea the dataArea to set
     */
    public void setDataArea(DataArea dataArea) {
        this.dataArea = dataArea;
    }

    public ApplicationArea getApplicationArea() {
        return applicationArea;
    }

    public void setApplicationArea(ApplicationArea applicationArea) {
        this.applicationArea = applicationArea;
    }
}

现在，在应用程序xml的情况下，它运行良好，请求结构的根元素为getPerson，但在JSON请求的情况下，它不会显示根元素getPerson。我知道有一些名为 WRAP_ROOT_VALUE 的东西可用于在json的情况下启用根名称。但问题是我不知道如何使用camel-config.xml。

如何通过camel-config.xml设置WRAP_ROOT_VALUE或者还有其他方法。提前谢谢..

Json Root Name不会进入Camel Swagger休息服务

0 个答案: